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gizmo_the_mogwai [7]
3 years ago
7

PLEASE HELP I WILL MARK BRAINLIEST

Mathematics
1 answer:
Papessa [141]3 years ago
8 0

Answer:

a) 53%

b) 12%

Step-by-step explanation:

you need to use the equation given

y = -6.83x + 108

x is the rank

y is the probability of winning 1st game

a) for rank 8th or x=8

y = -6.83(8) + 108 = 53.36 or 53%

b) for rank 14th or x=14

y = -6.83(14) + 108 = 12.38 or 12%

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Solve the system of equation
nikdorinn [45]

Answer:

So the Point of intersection is (-4,-2)

Which is option A

Step-by-step explanation:

The given system of equations is

-0.1x - 0.8y = 2              ...................(i)

0.6x - 0.5y = -1.4           ...................(ii)

Let us take equation (i) and use method of substitution for solving it

the equation (i) is

-0.1 x - 0.8y = 2

Adding 0.8y on both sides

-0.1 x + 0.8 y - 0.8 y = 2 + 0.8 y

-0.1 x = 2 + 0.8 y

Dividing both sides -0.1

\frac{-0.1 x}{-0.1}=\frac{0.8 y}{-0.1}+\frac{2}{-0.1}

x = -8 y - 20                     ..........................(iii)

Now we will use this value and put it into equation (ii) to find the value of y

Equation (ii) is

0.6 x - 0.5 y = -1.4

Put value of x

0.6(-8 y - 20) - 0.5 y =-1.4

It becomes

-4.8 y - 12 - 0.5 y = -1.4

adding 12 on both sides

-4.8 y - 0.5 y - 12 + 12 = -1.4 + 12

it becomes by solving

-5.3 y = 10.6

Dividing both sides by -5.3

\frac{-5.3*y}{-5.3}=\frac{10.6}{-5.3}

So

y = -2

Now we have the value of y putting it in equation (iii)

Equation (iii) is

x = -8 y - 20    

Putting value of y

x = -8*(-2) - 20

x = 16-20

x=-4

So the Point of intersection is (-4,-2)

7 0
3 years ago
How much more would $1000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the inte
choli [55]
\bf ~~~~~~ \textit{Compounding Continuously Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
t=years\to &5
\end{cases}
\\\\\\
A=1000e^{0.037\cdot 5}\implies A=1000e^{0.185}\\\\
-------------------------------\\\\

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &5
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.037}{4}\right)^{4\cdot 5}\implies A=1000(1.00925)^{20}

compare both amounts.
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LuckyWell [14K]
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Vaselesa [24]

Answer:

Step-by-step explanation:

2. 3x-1/3 = 5

+1/3    +1/3

___________-

3x= 5   1/3

÷3     ÷3

__________________

x=1.77777777778

5.  3x-9=5x-3

+3     +3

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3x-6=5x

-3x    -3x

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-6=2x

÷2    ÷2

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-3=x

8.   3x-2x=8  ( I crossed multiplied btw)

x=8

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