We calculate the z-score, by evaluating the z value of 0.96/2 = 0.48
The z-score for 0.48 = 2.054
Next, we multiply the z-score by the standard deviation.
i.e. 2.054 x 15 = 30.81
Next, we divide by the margin of error. (from the question, we want to estimate to within 3 minutes of the mean, thus our margin of error is 3.)
i.e. 30.81 / 3 = 10.27
Finally, we square the outcome,
i.e. 10.27^2 = 105.47
Therefore, to estimate within 3 minutes of the mean with 96% confidence, the researcher should take a minimum of 106 samples.
Answer:
the probability having no customers are in the system is 0.375
Step-by-step explanation:
The computation of the probability having no customers are in the system is as follows;
Given that the arrival rate is 1.25 customers per minute
The Service rate is 2 customers per minute
Based on the above information, the probability is
Hence, the probability having no customers are in the system is 0.375
Answer:
268,770 AU i think im not to sure
Step-by-step explanation:
