3 years ago

Find the distance and midpoint of the following points: (3, 2) and (8, 9)

Mathematics

1 answer:

azamat3 years ago

6 0

Answer:

Midpoint:

$\frac{3 + 8}{2} = 6.5 \: \: \: \: \frac{2 + 9}{2} = 6.5 \\ (6.5 \: and \: 6.5) \\ \\ distance - \sqrt{(8 - 3) {}^{2} + (9 - 2) {}^{2} } \\ \sqrt{25 + 49} = \sqrt{74}$

You might be interested in

If y = 16 when x = 4, find Y when x = 6

Zigmanuir [339]

Y would equal 24 :)

6 0

3 years ago

What is the least common multiple of 4 and 6? * 1. 24 2. 12 3. 4 4. 6

azamat

Answer:

Step-by-step explanation:

6 0

3 years ago

Convert x2 + y2 -4x = 0 to polar form.

Bingel [31]

Answer:

$r(r-4\cos \theta)=0$

Step-by-step explanation:

We are given the following equation:

$x^2 + y^2 -4x = 0$

We have to convert it into polar form.

We put

$x = r \cos \theta\\y = r\sin \theta$

Putting values, we get:

$x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0$