Answer:
Part B: 8 and 2 (more answers ofc)
Part C: Two more dots on 6 (more than one answer tho)
Step-by-step explanation:
<em>Part B:</em>
The added number of dots is 39 at the beginning and the mean is 3.9. (39/10). Since we have to add 2 dots the equation will be (<em>39 + ? + ?) / 12 = Less than 3.9</em>. We also need the range to increase. This means that one of the blanks must be larger than 7 (the largest dot on the dot plot!) I just went with 8 to keep the mean as small as possible. This leaves 1 more blank to figure out. There are multiple answers to this problem but I went with 2 just because then the mean would be 3.5 a better answer than something like 3.58333333333.
<em>Part C:</em>
If you think about it all the dots added up should be 6x12 = 72. Currently all the dots add up to 60. 72-60 is 12. This means that 12 is equal to 2 dots. I guess you could also do 5 and 7, 8 and 4, etc.
G'day
-birb
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
Therefore the reminder is 3 when 5n is divided by 7.
Step-by-step explanation:
we know that
Dividend = quotient × Divisor +Reminder
⇔ n = Q(n) × 7 + 2 [ let Q(n) is quotient]
multiplying by 5 both sides
5n = 5 Q(n) ×7 + 2×5
⇔5n = 5 Q(n) ×7 +10
⇔5n= 5 Q(n) ×7 +7 +3
⇔ 5n = (5Q(n) +1) × 7 +3
Therefore the reminder is 3 when 5n is divided by 7.
Answer:
i dont think b is correct because x(x)(x) would be x ^3
Step-by-step explanation:
if you put in 5 as an example then you would see that 5(5)(5) is actually 125 and not 15 like 3 times 5
