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3 years ago

How many 4 digit palindromes contain both the digits 1 and 2

Mathematics

1 answer:

Norma-Jean [14]3 years ago

8 0

What a clever sneaky little problem !

There can only be two of them: 1221 and 2112 .

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Papa John's sold 50 pizzas on Monday. Of the pizzas sold, 35 of them were delivered. What percent were delivered?

Charra [1.4K]

Answer:

75%

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the area of the figure? Explain.

Dominik [7]

Answer:

24 cm²

Step-by-step explanation:

The rectangular section on the right is 8 - 4 = 4 cm wide.

It is 3 + 1.5 = 4.5 cm tall.

The area of the rectangular section is ...

A = LW

A = (4.5 cm)(4 cm) = 18 cm²

The triangular section on the left is 4 cm wide and 3 cm high. Its area is ...

A = 1/2bh

A = 1/2(4 cm)(3 cm) = 6 cm²

The total shaded area is the sum of the areas of the triangular section and the rectangular section:

area = 18 cm² +6 cm² = 24 cm² . . . area of the figure

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3 years ago

Capacity planning answers the question "__________"

Greeley [361]

Answer:

How to be more efficient and how to pay for a project.

Hope it helps!

Step-by-step explanation:

5 0

3 years ago

you talk on the phone y minutes on a day x of every month according to the equation y=2x+1. The cellphone company claims you tal

Mademuasel [1]

No they are not , y= 2(4)+1 is 9 not 12

4 0

4 years ago

Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.

il63 [147K]

Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

7 0

4 years ago