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lyudmila [28]
3 years ago
13

The domain of y=ax^2 is all real numbers. Describe the range when (a) a>0 and (b) a<0.

Mathematics
1 answer:
eduard3 years ago
3 0
The range is all positive values...

R{y | y>0}

Range > "Y" such that y is greater than 0
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Solution :

Assuming $\sigma_1^2=\sigma_2^2$

We have to test

$H_0:\mu_1=\mu_2$

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$s_p=\sqrt{\frac{(n_1-1)s_1^2+ (n_2-1)s_2^2}{n_1+n_2-2}}$

$s_p=\sqrt{\frac{(25-1)(425)^2+ (20-1)(415)^2}{25+20-2}}$

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Under H_0, the t-statistics is as follows:

$t=\frac{(\overline{x_1} - \overline{x_2})}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} \sim $             $\text{t with }(n_1+n_2-2) \ DF$

$t=\frac{(7200-7087)}{(420.6107)\sqrt{\frac{1}{25}+\frac{1}{20}}}$

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DF = (25 + 20 - 2)

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Step-by-step explanation:

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Step-by-step explanation:

Hey there!

Here;

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Now, Using Pythagoras relation;

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Put all values.

h =  \sqrt{ {24}^{2}  +  {10}^{2} }

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<u>ANS</u><u>:</u><u> </u><u>OPTIO</u><u>N</u><u> </u><u>A</u><u>.</u>

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