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lyudmila [28]
3 years ago
13

The domain of y=ax^2 is all real numbers. Describe the range when (a) a>0 and (b) a<0.

Mathematics
1 answer:
eduard3 years ago
3 0
The range is all positive values...

R{y | y>0}

Range > "Y" such that y is greater than 0
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#7. What are the values/ how do I do it
Tasya [4]

Answer:

x =2

SK = 21

KY = 13

SY = 34

Step-by-step explanation:

we can see from the picture the following:

SK + KY = SY  equation 1

SK=13x-5    equation 2

KY = 2x+9    equation 3

SY = 36-x     equation 4

using equation 2, equation 3 and equation 4 in equation 1 we have:

13x - 5 +  2x + 9 = 36-x  

15x +4 = 36 - x

15x +x = 36-4

16x = 32

x = 32/16

x= 2

using x as 2 we evaluate it in equation 2, equation 3 and equation 4:

SK=13(2)-5 = 21

KY= 2(2) +9 = 13

SY = 36-2 = 34

5 0
3 years ago
Functions.
never [62]

Answer:

2,5 and 6

Step-by-step explanation:

The answer is going to be option 2, 5 and 6 because the line touches -4,2 and 4 on the x axis. And these are the x values so that's why this is going to be the answer.

Hope this information helps you!

4 0
3 years ago
If sec x = -2 and x is an angle in the second quadrant find tangent
faltersainse [42]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
The following formula relates 3 equantities: force(F),mass(m),and acceleration(a)
weqwewe [10]
We know, Force = mass × acceleration


( i ) :

Given,
Force = 25 units
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Solution,

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⏩ 25 / 10 =acceleration

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( ii ) :


Given,
Force = 25 units
Acceleration = 5 units
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Solution :

Applying formula,
➡ Force = mass × acceleration

⏩ 25 = 5 × mass

⏩ 25 / 5 = mass

⏩ 5 units = mass



\:
5 0
3 years ago
Mr. Berger assigned the following system of equations to be solved for homework. 2x-3y = -12
jeka57 [31]
-4x + 6y = 24
4x + y = -10

7y = 14

y = 2

2x - 6 = -12

2x = -6

x= -3

6 0
3 years ago
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