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cestrela7 [59]
3 years ago
8

How many solutions does the system of equations have?

Mathematics
2 answers:
Finger [1]3 years ago
8 0
Answer:
A.

explanation::
Anestetic [448]3 years ago
6 0

Answer:

no solution

Step-by-step explanation:

a solution would mean a point where the two lines cross. theres no such thing for parallel lines.

but if the lines are the same, they are parallel and cross everywhere, that would give infinite solutions.

if they would cross once, it would mean one solution

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last year, Nicole biked n miles. This year, she biked 524 miles. Using n, write an expression for the total number of miles she
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n+524

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216 as a power number
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Hey There,

216 is equal to 6^{3}

Solution:

6*6*6=213

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In need of help with this question .
Andreyy89
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3 years ago
Two lemon creams plus four fudge cookies have 450 calories. Four lemon creams plus two fudge cookies have 420 calories. How man
Gnoma [55]

Answer:

Each fudge cookie has 80 calories.

Each lemon cream has 65 calories.

Step-by-step explanation:

We will let \ell represent the calories in lemon creams and f represent the calories in fudge cookies.

Two lemon creams and four fudge cookies together have 450 calories. So, we can write the following equation:

2\ell+4f=450

And four lemon creams plus two fudge cookies together have 420 calories. So, we can write the following equation:

4\ell+2f=420

We now have a system of equations. We can solve this by elimination.

For the first equation, we can multiply both sides by -2. This way, the \ell will cancel when we add the two equations together.

So, the first equation becomes:

-4\ell-8f=-900

Add this to the second equation. Hence:

(-4\ell+4\ell)+(-8f+2f)=(-900+420)

Simplify:

-6f=-480

Divide both sides by -6. Hence:

f=80

So, there are 80 calories in one cookie.

We can use the first equation again to find the amount of calories in one cream. We have:

2\ell+4f=450

Substituting 80 for f yields:

2\ell+320=450

Then it follows that:

\ell=65

So, there are 65 calories in each lemon cream.

5 0
2 years ago
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