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musickatia [10]
3 years ago
9

Convert to a scientific notation  860,000,000,000 =

Mathematics
2 answers:
valentina_108 [34]3 years ago
4 0
8\underbrace{60,000,000,000}_{\leftarrow11}=8.6\times10^{11}
prohojiy [21]3 years ago
3 0
8.60 x 10 raised to the 11 power

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In a bag of blue and yellow marbles, the ratio of blue marbles to yellow marbles is 3:5. if the bag contains 60 yellow marbles,
fiasKO [112]
Double the numbers by themselves for 5 times and you get the ration of blue to yellow balls of 96:60
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A helicopter flies 665 feet above ground. What is the measure of the angle of depression from the helicopter to the girl’s line
grigory [225]
67 is the correct answer trust me i just answered and got it correct.
8 0
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The March utility bills (in dollars) of 30 homeowners are listed below. 44 38 41 50 36 36 43 42 49 48 35 40 37 41 43 50 45 45 39
Ulleksa [173]

Step-by-step explanation:

What we will do is create a table with the data they give us, the first thing will be to organize it from smallest to largest, like this:

33, 35, 35, 36, 36, 36, 37, 38, 38, 39, 40, 40, 41, 41, 41, 42, 42, 43, 43, 43, 44, 45, 45, 47, 48, 48, 49, 50, 50, 50

Now we know that the smallest number is 33 and the largest is 50, to create 5 ranges, we will calculate the difference and divide by 5.

(50 - 33) / 5 = 3.4

Therefore we will make ranges of 3 and 4, values, like this

Rank 1: 33 - 36

Rank 2: 37 - 39

Rank 3: 40 - 43

Rank 4: 44 - 46

Rank 5: 47 - 50

We will calculate the frequency distribution of values in each range:

Rank 1: 6

Rank 2: 4

Rank 3: 10

Rank 4: 3

Rank 5: 7

5 0
3 years ago
The value of the 4th term is 80. the sequence is being doubled each step what is the 7th term?
leva [86]
This is a geometric sequence with common ratio (r) = 2.
an = ar^(n - 1)
a4 = a(2)^(4 - 1) = a(2)^3 = 8a
8a = 80
a = 80/8 = 10

7th term (a7) = 10(2)^(7 - 1) = 10(2^6) = 10(64) = 640
8 0
3 years ago
What two numbers' sum=-4 and product=-2
n200080 [17]

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

<em>b</em> = -2 - √6

In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

7 0
2 years ago
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