All categories

2 years ago

A scuba diver dove 313 feet below sea level then rose 26 feet?

Mathematics

2 answers:

grigory [225]2 years ago

7 0

287 is the answer

313 - 26 = 287

klasskru [66]2 years ago

3 0

Answer:

I think the answer would be 287?

Step-by-step explanation:

You might be interested in

Line segment QR is dilated to create line segment Q'R' using the dilation rule DT,1.5. Point T is the center of dilation. Line s

velikii [3]

Answer:

$y= 3$

Step-by-step explanation:

Given

$RT = 6$

$k = 1.5$ --- dilation ratio

See attachment

Required

Determine length, y

First, we calculate length R'T.

Since point T is the center of dilation, then:

$R'T = k * RT$

Substitute known values

$R'T = 1.5 * 6$

$R'T = 9$

y is between R'T and RT;

So:

$y = R'T - RT\\$

$y = 9 -6$

$y= 3$

5 0

2 years ago

Read 2 more answers

Quick HELP Please! I will give BRAINLIEST !!! I’m So confused

drek231 [11]

For a your meant to draw a graph (I don’t know what graph) and for b use the domain to figure out the minimum and maximum range values

6 0

3 years ago

.194 times a million 1.94x10^5 19.4x10^-4 194x10^3 1.94x10^-5

Anit [1.1K]

Answer:

All of them are 194000 except 19.4x10^-4

Step-by-step explanation:

math

7 0

2 years ago

So just read yhe picture please

const2013 [10]

The correct answer is B). 6

Radius of inscribed circle of triangle HJK is 6 unit

Step-by-step explanation:

As shown in figure,

The triangle HJK has In-circle or inscribed circle of radius PL(or PM or PN)

Since, PL and PM is radius of same in-circle,

PL = PM

Given that PL=3x+4 and PM =6x-14

3x+4=6x-14

3x=18

x=6

Thus, The correct answer is B). 6

6 0

2 years ago

Is f(x) continuous at x equals 4? Why or why not? A. No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit

soldier1979 [14.2K]

Corrected Question

Is the function given by:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

continuous at x=4? Why or why not? Choose the correct answer below.

Answer:

(D) Yes, f(x) is continuous at x = 4 because $Lim_{x \to 4}f(x)=f(4)$

Step-by-step explanation:

Given the function:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

A function to be continuous at some value c in its domain if the following condition holds:

f(c) exists and is defined.

$Lim_{x \to c}$ f(x)$ exists.

$f(c)=Lim_{x \to c}$ f(x)$

At x=4

$f(4)=\dfrac{1}{4}*4+1=2$

$Lim_{x \to 4}f(x)=2$

Therefore: $Lim_{x \to 4}f(x)=f(4)=2$

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0

2 years ago