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3 years ago

There are 3 consecutive integers with a sum of 69. what are they?

Mathematics

1 answer:

Nostrana [21]3 years ago

5 0

The integers can be represented by x, x+1 and x+2

x+x+1+x+2=69
3x+3=69
3x=66
x=22

Final answer, 22+23+24

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Yuri [45]

P-x= -10
Now to isolate x divide both sides by p
-x = -10/p
But x can not be a negative do distribute a negative 1 to both sides and your answer is :
x = 10/p

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3 years ago

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If you have a bit of honesty and sincerity, kindly avoid spamming just for points!

Kruka [31]

Answer:

29.12%

Step-by-step explanation:

Given that :

A = 49

B = 50

C = 38

D = 60

E = 75

Total = (49 + 50 + 38 + 60 + 75) = 272

Pie chart % for each :

A = (49 / 272) * 360 = 64.85

B = (50 / 272) * 360 = 66.18

C = (38 / 272) * 360 = 50.29

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2 years ago

Brainliest question please help please help me now plz

Kruka [31]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d\sqrt{(y2-y1)^2+(x2-x1)^2 }$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

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2 years ago

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