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4 years ago

Is it linear or not if it's not explain

Mathematics

1 answer:

riadik2000 [5.3K]4 years ago

8 0

It is linear... x is increasing by 2 and y is increasing by 7 each time

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Find the distance between (2, -3) and (14, -16). Round to the nearest 10th if necessary.

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17.7 or 18snzusb disms

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3 years ago

A stack of cards is numbered 1 to 21. Kelly pulls one card from the stack. What is the best approximation for the probability th

ASHA 777 [7]

The correct answer is 48%

There are 10 even numbers from 1 to 21.

That makes the probability of an even number 10 out 21.

10 / 21 x 100 = 48%

8 0

4 years ago

Can someone help with this please.<br><br>

sergeinik [125]

Simplified
2/5x-5-1/3
2 x -5 - 1/3
5
-10/5 - 1/3
-2 - 1/3
-7/3

4 0

3 years ago

Read 2 more answers

What type of quadrilateral is created by the points:<br><br> L (-5,4), M (2,2), N (0,-3), S (-7,-1)

kumpel [21]

Given same lengths and slopes of the opposite sides and nature of the angle between adjacent sides, we have;

The type of quadrilateral is a parallelogram

<h3>How can the type of quadrilateral be found?</h3>

The given points are;

L(-5, 4), M(2, 2), N(0, -3), S(-7, -1)

Lengths of the sides are;

Length of LM = √((2-(-5))²+(2-4)²) ≈ √(53)

Length of MN = √((2-0)²+(2-(-3))²) ≈ √(29)

Length of NS = √((0-(-7))²+((-3)-(-1))²) ≈ √(53)

Length of LS = √(((-7)-(-5))²+((-1)-4)²) ≈ √(29)

Therefore;

The lengths of opposite sides are the same.

Slope of LM = (2-4)/(2-(-5)) = -2/7

Slope of MN = (2-(-3))/(0-2) = 5/2

Slope of NS = ((-3)-(-1))/(0-(-7)) = -2/7

Slope of LS = ((-1)-4)/(-7-(-5)) = 5/2

Therefore;

The opposite sides are parallel, and

The the adjacent sides are not perpendicular

The quadrilateral created by the points L(-5, 4), M(2, 2), N(0, -3), S(-7, -1) is therefore;

A parallelogram

Learn more about parallelograms here:

brainly.com/question/1100322

#SPJ1

8 0

2 years ago

Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4

riadik2000 [5.3K]

<h3><em>The complete question:</em></h3>

<u><em> </em></u><u>Harold uses the binomial theorem to expand the binomial </u> $(3x^5 -\dfrac{1}{9}y^3)^4$ <u />

<u>(a) What is the sum in summation notation that he uses to express the expansion? </u>

<u>(b) Write the simplified terms of the expansion.</u>

Answer:

(a). $(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$$

(b). $(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}$

Step-by-step explanation:

(a).

The binomial theorem says

$(x+y)^n=$$\sum_{k=0}^{n} \binom{n}{k}x^{n-k}y^k $$$

For our binomial this gives

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n} \binom{4}{k}x^{4-k}y^k $$}$

(b).

We simplify the terms of the expansion and get:

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4$

$$$\sum_{k=0}^{n} \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4$

$\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561} }$

3 0

3 years ago