You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
The answer is
<h2>44 ft</h2>
Step-by-step explanation:
The figure above is a rectangle
To find the perimeter of a rectangle we use the formula
Perimeter of a rectangle = 2l + 2w
where
l is the length of the rectangle
w is the width of the rectangle
From the question
length = 14 ft
width = 8ft
Substituting the values into the above formula we have
Perimeter = 2(14) + 2(8)
= 28 + 16
We have the final answer as
<h3>Perimeter = 44 ft</h3>
Hope this helps you
Answer:
B
Step-by-step explanation:
Secant-secant with vertex outside the circle
1/2(larger-smaller arc)
1/2(114-36)
1/2(78)
39
A subtraction problem can be turned in to an addition problem because of negative numbers. Take 5-2=3 for example. If you change 5-2 into an addition problem then you would but he addition sign and a negative sign on 2. This will then leave you with the problem looking like 5+ -2. If you add 5 and -2 you will still get three.