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3 years ago

How do I solve 12=3 (2x-10)+6

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

6 0

Subtract 6 from both sides and you get 6=3(2x−10)

Divide both sides by 3 and you get 6/3=2x−10 and 6/3=2 so 2=2x−10

then add 10 to both sides 2+10=2x and you get 12=2x divide by 2

x=6 then check your answer and you get 12=12

PilotLPTM [1.2K]3 years ago

3 0

Hello.

1. switch sides

3(2x-10)+6=12

2.subtract 6 from both sides

3(2x-10)+6-6=12-6

3. simplfy

3(2x-10)=6

4. divide both sides by 3

3(2x-10)/3=6/3

5. simpfly

2x-10=2

6. add 10 to both sides

2x-10+10=2+10

7 simpfly

2x=12

Answer=6

have a nice day

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