Together with some anthropologists, you’re studying a sparsely populated region of a rainforest, where 50 farmers live along a 5
0-mile-long stretch of river. Each farmer lives on a tract of land that occupies a 1-mile stretch of the river bank, so their tracts exactly divide up the 50 miles of river bank that they collectively cover. (The numbers are chosen to be simple and to make the story easy to describe.)
The farmers all know each other, and after interviewing them, you’ve discovered that each farmer is friends with all the other farmers that live at most 20 miles from him or her, and is enemies with all the farmers that live more than 20 miles from him or her.
The farmers all know each other, and after interviewing them, you’ve discovered that each farmer is friends with all the other farmers that live at most 20 miles from him or her, and is enemies with all the farmers that live more than 20 miles from him or her.
1 answer:
Answer:
Explanation:
Farmers are always both directly and indirectly connected to each other
Their network is mostly strong
Networks become weak only on the edges (ends) of the river but doesn't completely dimnish
With the available network length, the center of river bank forms the strongest network of all and becomes a key player in defining the balance property of overall network
The network is very well structurally balanced and we can see that through the below image
20 miles 10 20 30 40 50
See attachment file for diagram
Considering the total length of river as 50miles and and the center of the whole length will be at 25th mile. From that point, if we consider a farmer will be be having friends for a length of 20miles both along upstream and downstream.
By this he'll be in friend with people who are around 80% of the total population. As me move from this point the integrity increases and this results in a highly balanced structural network.
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<h2>Answer:</h2>
//import the Scanner class to allow for user input
import java.util.Scanner;
//Begin class definition
public class FirstAndLast{
//Begin the main method
public static void main(String []args){
//****create an object of the Scanner class.
//Call the object 'input' to receive user's input
//from the console.
Scanner input = new Scanner(System.in);
//****create a prompt to tell the user what to do.
System.out.println("Enter the string");
//****receive the user's input
//And store it in a String variable called 'str'
String str = input.next();
//****get and print the first character.
//substring(0, 1) - means get all the characters starting
//from the lower bound (index 0) up to, but not including the upper
//bound(index 1).
//That technically means the first character.
System.out.print(str.substring(0,1));
//****get and print the last character
//1. str.length() will return the number of character in the string 'str'.
//This is also the length of the string
//2. substring(str.length() - 1) - means get all the characters starting
// from index that is one less than the length of the string to the last
// index (since an upper bound is not specified).
// This technically means the last character.
System.out.print(str.substring(str.length()-1));
} // end of main method
} //end of class definition
<h2>Explanation:</h2>The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.
The source code and a sample output have also been attached to this response.
To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java
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java
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