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earnstyle [38]
3 years ago
13

Can someone solve and explain this question plz​

Mathematics
1 answer:
oee [108]3 years ago
4 0

firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,

\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{z}{5}-4=\cfrac{7}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15\left( \cfrac{z}{5}-4 \right)=15\left( \cfrac{7}{3} \right)}\implies 3z-60=35 \\\\\\ 3z=95\implies z=\cfrac{95}{3}\implies z = 31\frac{2}{3}

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3 years ago
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Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).

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Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:

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Now lets divide both sides by b to make an a/b appear:

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Finally, multiply both sides by (1/2) or divide by 2:

(2a/b)/2 = 2

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This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.

7 0
4 years ago
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Umnica [9.8K]

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Hope This Helps!!! :D  

3 0
3 years ago
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