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3 years ago

What is the domain and range of the set? {(2,2.3),(5,2.3), (7,15)}

Mathematics

1 answer:

aleksandrvk [35]3 years ago

3 0

Answer:

DOMAIN: 2, 5, 7

RANGE: 2.3, 2.3, 15

Step-by-step explanation:

Domain is always the first value of the set, and range is always the second value of the set. Hope it makes sense, and that it helped.

Have a good day! goodluck.

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Y = -3x+4 and y= 1/2x-3

Papessa [141]

Answer:

{x = 2 , y = -2

Step-by-step explanation:

Solve the following system:

{y = 4 - 3 x | (equation 1)

{y = x/2 - 3 | (equation 2)

Express the system in standard form:

{3 x + y = 4 | (equation 1)

{-x/2 + y = -3 | (equation 2)

Add 1/6 × (equation 1) to equation 2:

{3 x + y = 4 | (equation 1)

{0 x+(7 y)/6 = (-7)/3 | (equation 2)

Multiply equation 2 by 6/7:

{3 x + y = 4 | (equation 1)

{0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 6 | (equation 1)

{0 x+y = -2 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 2 | (equation 1)

{0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 2 , y = -2

8 0

3 years ago

In a large on-the-job training program, half of the participants are female and half are male. In a random sample of six partici

Radda [10]

Answer: 0.9844

Step-by-step explanation:

given data:

sample size n = 6

It’s assumed that half the population are male and the remaining half are females

F = 1/2

M = 1/2

the probability that the investigator would draw altleats one male

P ( x ≥ 1 ) =

= 1 - ( 0.5 ) ^ 6

= ( 0.5 )^6

= 0.9844

5 0

3 years ago

What point the equation

Maslowich

Answer:

The Answer to the question is C

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What fraction is closest to 3/4?

kykrilka [37]

Let's start by finding a common denominator for all of these fractions. In this case, we will use 60.
3/4 = 45/60
2/3 = 40/60
3/5 = 36/60
7/10 = 42/60
13/20 = 39/60

The closest to 45/60 is 42/60/ Therefore, 7/10 is the closest to 3/4

4 0

3 years ago

Read 2 more answers

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

3 years ago

Read 2 more answers