An earthquake is the result of a sudden release of stored energy in the earths crust that creates seismic waves.
Answer:
<em>Hox </em>Gene
Explanation:
First, you're question is very vital, there are many ways in classifying along with identifying all living organisms that includes; morphological analysis, molecular systematics (studying the similarities and differences of the genetic data such in the sequences of DNA, RNA, and rRNA ), homology, cladistics, etc. based on phylogenetic tree, which the study of the evolutionary among various species.
But through it said that all living organisms shared one common ancestor. However, what makes them different from one to another is the homeotic genes that called <em>Hox </em>Genes; which specify the fate of a particular segment or region of the body, meaning the number and arrangements of the<em> Hox</em> genes varies considerably among different types of animals.
For instance, Sponges have at least one homologous to<em> Hox</em> genes, also insects have nine or more <em>Hox </em>genes resulting in multiple <em>Hox </em>genes occur in a cluster in which the genes are close to each other along a chromosome. Therefore, increases in the number of<em> Hox</em> genes have been instrumental in the evolution of many animals species with greater complexity in body structure.
Overall, more <em>Hox</em> genes, more complexity in body structure resulting in the differences of their morphological structure.
Hope that answered your question!
After a caterpillar eats a leaf, it can convert the chemical energy into mechanical energy to help it build a cocoon.
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Answer:
Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.
Given:
R1R1 = 42
R2R2 = 39
R1R2 = 86
Total R1 alleles = 2*42+86 = 170
Total R2 alleles = 2*39+86 = 164
Total alleles = 334
Frequency of allele R1 = 170/334 = 0.51
Frequency of allele R2 = 164 / 334 = 0.49
Expected number of each phenotype:
Total population = 167
Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44
Green = R2R2 = 0.49 * 0.49 * 167 = 40.10
Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46
Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E
Blue 42 43.44 -1.44 2.0736 0.0477
cyan 86 83.46 2.54 6.4516 0.0773
green 39 40.1 -1.1 1.2100 0.0302
Total 167 167 0.1552
Chi-square value = 0.155
Degrees of freedom = no. of phenotypes – 1
Df = 3-1 = 2
Critical value = 5.99
Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.
