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2 years ago

11

Find the first five terms that correspond with the following expression. 4n + 2

1 answer:

Lorico [155]2 years ago

7 0

Answer:

6,10,14,18,22

Step-by-step explanation:

4n+2

Let n=1 4(1)+2 = 4+2 = 6

Let n=2 4(2)+2 = 8+2 = 10

Let n=3 4(3)+2 = 12+2 = 14

Let n=4 4(4)+2 = 16+2 = 18

Let n=5 4(5)+2 = 20+2 = 22

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Rewrite the following in the form log(c).<br> log(10) - log(2)

serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

log(10/2)

log 5

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3 years ago

I Need Help With 9 And 10Please Help

Burka [1]

9: the answer is 4 to 13
10: the answer is 6 to 13

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3 years ago

What is the value for y?<br> Enter your answer in the box.<br> y=

serious [3.7K]

Answer:

$y =112$

Step-by-step explanation:

Given

The attached triangle

Required

Find y

The attached triangle is isosceles; so:

$x - 5=34$

Also, we have:

$y + x - 5 + 34=180$ --- angles in a triangle

Substitute: $x - 5=34$

$y + 34 + 34=180$

Collect like terms

$y =- 34 - 34+180$

$y =112$

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3 years ago

. Twelve coworkers go out for lunch together and order three pizzas. Each pizza is cut into eight slices. If each person gets th

fomenos

Answer: each person gets 2 slices of pizza

Step-by-step explanation: 3 pizza 8 slices each pizza 3•8=24 divided by 12=2

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3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago