Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
6 Hours
Step-by-step explanation:
17,100 - 6,300= 10,800
10,800/1,800 = 6
Answer:
Hope 292.5 is right.
Step-by-step explanation:
First thing, multiply the triangles base and height which will give you 143 then divide it by two which is 71.5. Then to the parallelogram which is base times height which is 117. Moving on to the trapezoid, meanin one-hal times height times first base plus second base giving you 104. Finally, add'em up, giving you a total of 292.5.
Answer:
yes, if |a|=|b| then a = b......
Answer:3
Step-by-step explanation: