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3 years ago

Please solve this, 50 points and BRAINLIEST -4•6/7•-5/3

Mathematics

2 answers:

romanna [79]3 years ago

7 0

Answer:

40/7

Step-by-step explanation:

AleksandrR [38]3 years ago

4 0

Answer:

5 5/7

Step-by-step explanation:

-4•6/7•-5/3

Put the numbers as fractions

-4/1•6/7•-5/3

Rewriting

-4/1 * 6/3 * -5/7

Simplifying the middle fraction

-4/1 * 2/1 * -5/7

Multiply the first two terms

-8/1 * -5/7

Multiplying

40/7

Changing from an improper fraction to a mixed number

7 goes into 40 5 times with 5 left over

5 5/7

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The length of a rectangular house is two and a half times its width. Solve the problem using x to denote the shorter side of the

denpristay [2]

a. The construct the expression for the area of the rectangle in terms of x is y=2.5x

b. The area should be 2,560.

Given that,

the length of a rectangular house is two and a half times its width.

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a) The expression should be y = 2.5x

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Learn more: brainly.com/question/1301963?referrer=searchResults

3 0

2 years ago

Read 2 more answers

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$