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charle [14.2K]
3 years ago
14

Please help with 3 will give brainliest

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0
<h2>ADC is another way to name it.</h2><h2 /><h3><em>Please let me know if I am wrong.</em></h3>
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Find the measure of the missing angle
ipn [44]

Answer:

28 i think [⩾▾⩽]

Step-by-step explanation:

since this is a right angle, all you have to do is subtract 62 from 90 because a right angle is equal to 90 degrees.

hope this helps^^

have a great day :D

6 0
3 years ago
Read 2 more answers
Can someone please help me??
Semmy [17]

since we don't know any of your vocabulary, I might not be using the ones you learned


since we have points A and B and points F(A) and F(B), I think they want us to use the word 'translation'

"The function F(x) translates each point to the right without moving them up or down." would be my description


also the 2 lines are paralell


7 0
3 years ago
Complete the square and put this function in vertex form: f(x)=x^2+20x+97
Fofino [41]

Answer:

Step-by-step explanation:

f(x)=(x²+20x+100) -3  because : 97 = 100 -  3

f(x) = (x+10)² -3 ....vertex form

3 0
3 years ago
Need help<br> Pleaseeeee
fomenos

Answer:

164 m^2

Step-by-step explanation:

You can think of the shaded area in different ways. One of the ways is the entire outer colored rectangle minus the area of the small white rectangle inside.

The large colored rectangle is 12 m by 15 m.

The inner rectangle is 8 m tall. The width is 12 m - 5 m - 5 m = 2 m

A = 12 m * 15 m - 2 m * 8 m

A = 180 m^2 - 16 m^2

A = 164 m^2

4 0
3 years ago
Read 2 more answers
Find the matrix product, if possible.  Show your work please
steposvetlana [31]
\left[\begin{array}{ccc}-1&3\\5&4\end{array}\right] \cdot  \left[\begin{array}{ccc}0&-2&6\\1&-3&2\end{array}\right]\\\\=  \left[\begin{array}{ccc}(-1)(0)+(3)(1)&(-1)(-2)+(3)(-3)&(-1)(6)+(3)(2)\\(5)(0)+(4)(1)&(5)(-2)+(4)(-3)&(5)(6)+(4)(2)\end{array}\right]\\\\=  \left[\begin{array}{ccc}0+3&2-9&-6+6\\0+4&-10-12&30+8\end{array}\right]\\\\  =\left[\begin{array}{ccc}3&-7&0\\4&-22&38\end{array}\right]

3 0
3 years ago
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