The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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The value of scale k is 3
Step-by-step explanation:
In order to find the scale , we can either divide the coordinates of H' by the original point or compare both the points to find the original ordered pair.
Given
H(3,4)
H'(9,12)
The coordinates of H are multiplied with some integer k to form H'
So,
<u>For x-coordinate:</u>
3k = 9
k = 9/3 = 3
<u>For y-coordinate:</u>
4k = 12
k = 12/4 = 3
Hence,
The value of scale k is 3
Keywords: Coordinate geometry, scaling
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Answer:
Sample answer: The median of the means for Grade 8 is greater than for Grade 12. However, there is less variation in the data for Grade 12 since the length of the box for Grade 12 is shorter than the one for Grade 8.
Don't be worried friend :)
-(y + 2) + 8 = 3
=> -(y + 2) = -5
=> y + 2 = 5
=> y = 3
