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blondinia [14]
3 years ago
13

In a 6 team floor hockey league each team plays each of the other teams twice what is the total number of games played

Mathematics
1 answer:
Nana76 [90]3 years ago
7 0
It could be 12 or 72 depends on how your doing your math
You might be interested in
Why do you weigh more on earth than space?
Rama09 [41]

Hello there, Lithommie


You see accroding to newtons gravitational law an object that weighs more on earth wieghs less in space due to the lack of strenthness of gravity.


If my answer helped you understand more clearly i would glady apriciate brainliest thank you and have a great day!

6 0
2 years ago
A research engineer for a tire manufacturer is investigating tire life for a new rubber compound and has built 16 tires and test
frutty [35]

Answer:

The 95% confidence interval for mean tire life is between 52,368.4 kilometers and 67,911 kilometers.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 15 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.68

The margin of error is:

M = T*s = 2.1315*3645.94 = 7771.3

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60139.7 - 7771.3 = 52,368.4.

The upper end of the interval is the sample mean added to M. So it is 60139.7 + 7771.3 = 67,911.

The 95% confidence interval for mean tire life is between 52,368.4 kilometers and 67,911 kilometers.

3 0
2 years ago
Read 2 more answers
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
Read 2 more answers
2 over 3 n =-12 what value of n makes the equation true?
galina1969 [7]

Answer:

-1/18

Step-by-step explanation:

4 0
3 years ago
Round 399,411 to the nearest hundredth thousandth
melamori03 [73]
The nine rounds up so it would be 400,000
6 0
3 years ago
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