1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrej [43]
3 years ago
6

Please help I have another one similar but I just don't remember what the entire equation means.​

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

Step-by-step explanation:

you have to find what r and q is

You might be interested in
If i divide 3/4 with 2/5 what would the answer be​
Talja [164]

Answer:

The asnwer i fro 5/2 iss 2.5 and the other question is the answer is 1.3 is we add now is 3.8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
CALC- limits<br> please show your method
gladu [14]
A. Factor the numerator as a difference of squares:

\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6

c. As x\to\infty, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4

e. Let's first rewrite the root terms with rational exponents:

\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}

Next we rationalize the numerator and denominator. We do so by recalling

(a-b)(a+b)=a^2-b^2
(a-b)(a^2+ab+b^2)=a^3-b^3

In particular,

(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3
(x^{1/2}-x)(x^{1/2}+x)=x-x^2

so we have

\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}

For x\neq0 and x\neq1, we can simplify the first term:

\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x

So our limit becomes

\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43
3 0
3 years ago
How do the areas of the murals change when the width changes
kati45 [8]
 I do not completely understand your question, but if you mean area by "murals", then when the width increases, area does, too. For example:
I have a rectangular board that is 5 feet by 3 feet. The area is 15 square feet. I have another board with a longer width, but the same length. It is 5 feet by 4 feet. Its area is 20 square feet.
3 0
3 years ago
After your yearly checkup, the doctor has some bad news and some good news. The bad news is that you tested positive for a serio
Maru [420]

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

7 0
3 years ago
Soham's video game system measures 8 inches long, 6 inches wide, and 2 inches tall. Sean's video game system measures 1 inch lon
Lady_Fox [76]

Answer:

Combined volume of the two game systems  =416 cubic inches

Step-by-step explanation:

Volume of a cuboid = length × breadth × height

Soham's video game system measures 8 inches long, 6 inches wide, and 2 inches tall.

So,

Volume of Soham's video game system = 8 × 6 × 2 = 96 cubic inches

As Sean's video game system measures 1 inch longer on all sides,

the video game system measures 8+2=10 inches long, 6+2=8 inches wide, and 2+2=4 inches tall.

Volume of the video game system = 10 × 8 × 4 = 320 cubic inches.

Therefore,

Combined volume of the two game systems = 96+320=416 cubic inches

5 0
3 years ago
Other questions:
  • one side of a ship has marks spaced 3 feet apart. four marks are underwater. how many feet of the ship are underwater
    15·1 answer
  • 350/100 as a decimal and a percent
    13·2 answers
  • Write a formula to find the nth term of a geometric sequence -1/3,1/2,-3/4,9/8​
    13·1 answer
  • Gisele trains 7 days per week for a biathlon. She covers a total of 20 miles cycling and running each day. Gisele cycles a total
    9·2 answers
  • Function or not a function?
    6·2 answers
  • Please help if you can &lt;3
    7·1 answer
  • F r e e<br><br> <br><br> ara ARAAAAAAAA<br><br> say a joke pls i am sad ✋
    11·2 answers
  • Find the missing side length
    15·2 answers
  • Danny’s supermarket has 1 litter water bottles normally priced at $1.50 reduced 25%
    15·1 answer
  • Which expressions are equivalent to 2(4f + 2g)?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!