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Paha777 [63]
3 years ago
6

Select the correct answer. Given: `Delta`ABC, where AB = BC Prove: `"m"/_BAC = "m"/_BCA` Statement Reason 1. Let `Delta`ABC be a

n isosceles triangle with AB = BC. given 2. Create point D on side `bar(AC)` so `bar(BD)` bisects `/_ABC`. constructing an angle bisector 3. `"m"/_ABD = "m"/_CBD` definition of angle bisector 4. BD = BD Reflexive Property of Equality 5. `DeltaABD ~= DeltaCBD` 6. `"m"/_BAC = "m"/_BCA` Corresponding angles of congruent triangles have equal measures. What is the reason for statement 5 in this proof? A. ASA B. SSS C. AAS D. SAS
Mathematics
1 answer:
Leto [7]3 years ago
5 0

Since BD is the angle bisector of ∠ ABC,

∠ ABD = ∠ CBD --- (1)

Now, in triangles Δ ABD and Δ CBD,

BD = BD (common side)

∠ ABD = ∠ CBD from (1)

AB = BC (Given)

Hence, Δ ABD ≅ Δ CBD (SAS Rule).

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Answer: correct.

Step-by-step explanation:

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The abc company has a net income of $56.000, ASSETS AT BEGINNING OF YEAR ARE $263.000 AND ASSETS AT END OF YEAR ARE $313.000. wH
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Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

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Design a sine function with the given properties:
Rom4ik [11]

Answer:

f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13.

Step-by-step explanation:

Given information:

Period = 24 hr

Maximum = 16 at t=16 hr.

Minimum = 10 at t=4 hr.

The general sin function is

y=A+\sin(B(x-C))+D        .... (1)

where, |A| is altitude, \frac{2\pi}{B} is period, C is phase shift and D is midline.

Period is 24 hr.

24=\dfrac{2\pi}{B}\Rightarrow B=\dfrac{\pi}{12}

Altitude is

A=\dfrac{Maximum-Minimum}{2}=\dfrac{16-10}{2}=3

D=\dfrac{Maximum+Minimum}{2}=\dfrac{16+10}{2}=13

The function is minimum at t=4 and maximum at t=16,phase shift is

C=\dfrac{16+4}{2}=10

Substitute these values in equation (1).

y=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13

Therefore, the required function is f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13.

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