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3 years ago

5

Lily just lit a new candle and then let it burn all the way down to nothing. The initial length of the candle was 10 inches and

after burning for 10 hours, the candle's height was down to 5 inches. Write an equation for
L
,
L, in terms of
t
,
t, representing the length of the candle remaining unburned, in inches,
t
t hours after the candle was lit.

1 answer:

docker41 [41]3 years ago

6 0

I don’t know if you are in church today but if

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Find the value of x

Mashutka [201]

Answer:

x ≈ 15.9

Step-by-step explanation:

a straight line is equal to 180 degrees

so we now know that 9x + 8 + 29 = 180

combine like terms 9x + 37 = 180

now subtract 37 from both sides 9x = 143

now divide both sides by the value of 9 x ≈ 15.9

7 0

3 years ago

What part of 3 12 is 1/2 ? I need this asap

Aliun [14]

I assume you are asking one of three things, so I will answer all of them.

if you are asking what is 1/2 of 312, then multiply 312 by 1/2. 312 is really just 312/1, so
$312 \times \frac{1}{2} = \frac{312}{1} \times \frac{1}{2}$
we multiply fractions by multiplying straight across
$\frac{312 \times 1}{1 \times 2} = \frac{312}{2} = 156$

if you were asking what part of 3 1/2 is 1/2 then we have to recognize what 3 1/2 is as an improper fraction. to do this, we convert 3 into halves. how many halves of pizza are there in 3 whole pizzas? 6. so we have 6 halves and one half, which is a total of 7 halves.
$\frac{6}{2} + \frac{1}{2} = \frac{7}{2}$
now, we do the same thing as the first problem
$\frac{7}{2} \times \frac{1}{2} = \frac{7 \times 1}{2 \times 2} = \frac{7}{4}$

if you were asking what is half of 3.12, then we convert 1/2 to a decimal and multiply
$\frac{1}{2} = .5 \\ 3.12 \times .5 = 1.56$

6 0

3 years ago

he average movie admission price for a recent year was $7.18. The population variance was 3.81. A random sample of 15 theater ad

Gemiola [76]

Answer:

Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.

Step-by-step explanation:

The data given is

Population mean μ= $ 7.18

Population variance= σ²= 3.81

Population Standard Deviation = √σ²= √3.81= 1.952

Sample Mean= x`= $ 8.02

Sample Standard Deviation =s = $ 2.08

Sample Size = 15

Significance Level = ∝= 0.05

The null and alternate hypotheses are

H0: σ1=σ2 against the claim that Ha: σ1≠ σ2

where σ1 is the population variance and

σ2 is the sample variance

The rejection region is Z ≥ ±1.96 for two tailed test at ∝= 0.05

The test statistic z is used

z= x`- μ/ σ/√n

Putting the values

Z= 8.02-7.18/1.952/√15

z= 0.84/0.51599

z= 1.6279

Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.

3 0

3 years ago

New heat lamps are reported to have the mean lifespan of 100 hours with a standard deviation of 15 hours. Before replacing their

Tom [10]

Answer:

1

The correct option is C

2

The correct option is C

3

The correct option is A

4

The correct option is B

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 100$

The standard deviation is $\sigma = 15$

The sample size is $n = 36$

The sample mean is $\= x = 105.1$

Generally

The null hypothesis is $H_o: \mu = 100 \ hours$

The alternative hypothesis is $H_a : \mu \ne 100\ hours$

Given that the null hypothesis is true then the distribution of sample means $\mu_{\= x }$ , from a sample size of 36 is mathematically represented as

$\mu_{\= x } = \mu$

=> $\mu_{\= x } = 100$

According to the Central Limit Theorem the test stated in the question is approximately normally distributed if the sample size is sufficiently large $(n > 30 )$ so given that the sample size is large n = 36

Then the test is normally distributed and hence the standard deviation is 15

Generally the standard error of mean is mathematically represented as

$\sigma_{\= x } = \frac{ \sigma }{\sqrt{n} }$

=> $\sigma_{\= x } = \frac{15}{\sqrt{36} }$

=> $\sigma_{\= x } = 2.5$

Generally the approximate probability of observing a sample mean of 105.1 or more is mathematically represented as

$P( \= X \ge 105.1 ) =1 - P(\= X < 105.1) = 1- P(\frac{\= X - \mu }{\sigma_{\= x }}$

=> $P( \= X \ge 105.1 ) =1 - P(\= X < 105.1) = 1- P(Z$

From the z-table (reference calculator dot net )

$P(Z$

So

$P( \= X \ge 105.1 )= 1 - P(\= X < 105.1) = 1- 0.97932$

$P( \= X \ge 105.1 ) =0.02$

4 0

4 years ago

HELP URGENT NEED HELP

netineya [11]

0.6*3.98+1.8*2.49 =6.87 total cost

7 0

3 years ago