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beks73 [17]
2 years ago
14

Help, please, im failing math and really don't want to do it again next year.

Mathematics
1 answer:
DanielleElmas [232]2 years ago
3 0

Answer:

I really do love this type of questions....but in here it seems that the question in either incomplete or the answers are mixed...cause the DATA'S showing 8 digits while THE AGE OF PEOPLE is showing 7 digits

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What is the exact circumference of a circle with a radius of 17 millimeters?
anzhelika [568]
The equation of a circumference is 2\pir. Since we know that r=17, we plug that into the formula, and get an answer of C. 34
7 0
3 years ago
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Use slopes and y-intercepts to determine if the lines 10x+3y=−3 and 5x−4y=−3 are parallel.
kvasek [131]

Answer:

They are not parallel

Step-by-step explanation:

original equation

10x + 3y = -3

subtract 10x

3y = -10x - 3

divide by 3

y = -10/3x - 1

original equation

5x - 4y = -3

subtract 5x

-4y = -5x-3

divide by -4

y = 5/4x + 3/4

the slopes are not equal to each other (5/4x and -10/3x) so they are not parallel

4 0
1 year ago
Goal is to make $100. What % of the goal was met if raised $350?
slega [8]

______________________________

<h3>A = m ÷ t × 100</h3><h3>= $100 ÷ $350 × 100</h3><h3>= <u>28.6%</u></h3><h3>THE GOAL WAS SURPASSED BY 28.6%</h3>

______________________________

7 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
Every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she
gulaghasi [49]
26-28 I think although I'm not 100% sure
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3 years ago
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