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beks73 [17]
2 years ago
14

Help, please, im failing math and really don't want to do it again next year.

Mathematics
1 answer:
DanielleElmas [232]2 years ago
3 0

Answer:

I really do love this type of questions....but in here it seems that the question in either incomplete or the answers are mixed...cause the DATA'S showing 8 digits while THE AGE OF PEOPLE is showing 7 digits

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Determine whether the statement is always true, sometimes true, or never true. Give an example. (a) Both sides of an equation ca
arsen [322]

Answer:

(A) Always true

(B) Seldom true

Step-by-step explanation:

(A) Both sides of an equation can be multiplied by the same number without this action changing the solution of the equation.

Keyword here is "number".

Multiplying both sides of an equation by an equal quantity (same number) will result in same solution after solving for the unknown in the equation. This is because that numeric quantity can always be removed by dividing both sides of the equation by it or by a factor (or multiple) of it.

EXAMPLE:

For a linear equation, 4x - 6 = 15x

let's find the solution, in other words solve for the unknown value X.

4x - 15x = 6

-11x = 6

x = -6/11

Now multiply both sides of the equation by 3.

3(4x - 6) = 3(15x)

12x - 18 = 45x   ___new equation

Solve for X

12x - 45x = 18

-33x = 18

x = -18/33

Reduce the fraction to its simplest form by looking for a number that can divide both numerator and denominator without remainder. In other words, think of a number that is a factor of 18 and a factor of 33.

That common factor or highest common factor (HCF) is 3.

Go ahead and reduce the fraction.

x will be reduced to -6/11

(B) Both sides of an inequality can seldom be multiplied by the same number, without such action changing the solution set of the equation.

Inequalities are more complex. Operational signs even change sometimes, in the course of finding the solution set of the inequality.

Sometimes, multiplying both sides of an inequality by a given numeric quantity will change its solution set and sometimes, it won't.

5 0
3 years ago
HELP PLS!!! You invested ​$25,000 in two accounts paying 7% and 8% annual​ interest, respectively. If the total interest earned
Murljashka [212]
All u have to do is divide the answer is %3
4 0
3 years ago
300 miles is equal to how many yards
Novosadov [1.4K]
300 miles is equal to how many yards
= 528000

Hope this helps!
5 0
3 years ago
Read 2 more answers
I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x
joja [24]

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}

\mathbf{\rightarrow x = \dfrac{45}{20}}

\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}

\mathbf{\rightarrow x = \dfrac{9}{4}}

\mathbf{x \approx 2 \dfrac{1}{4}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
2 years ago
Read 2 more answers
[SOLVED] The following data values are amperage outputs from electrical testing.
valkas [14]

The median of the data is 64, the value of Q1 is 61.5, the value of Q2 is 71, and the value of Q3-Q1 is 9.5

<h3>What is the median?</h3>

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

We have data:

60, 60, 61, 62, 63, 63, 65, 65, 70, 72, 73, 98

The median = (63+65)/2 = 64

Q1 = (61+62)/2 = 61.5

Q2 = (70+72)/2= 71

Q3 - Q1 = 71 - 61.5 = 9.5

Thus, the median of the data is 64, the value of Q1 is 61.5, the value of Q2 is 71, and the value of Q3-Q1 is 9.5

Learn more about the median here:

brainly.com/question/21396105

#SPJ1

5 0
2 years ago
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