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3 years ago

Simplify Completely:

2 answers:

5 0

$5 \sqrt{162}-3 \sqrt{18}-4 \sqrt{98}= \\ 5\cdot 9 \sqrt{2}-3\cdot 3 \sqrt{2} -4\cdot 7\sqrt{2}=\\ 45 \sqrt{2}-9 \sqrt{2} -28\sqrt{2}=\\ 8 \sqrt{2}$

<span>B) 8√2 </span>

MaRussiya [10]3 years ago

3 0

The correct answer is (B)

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What is 3/9 =4/y y equals

mariarad [96]

Answer:

Y = 12

Step-by-step explanation:

3/9 = 4/y

By cross multiplying, we get

3*y = 4*9

3y = 36

Y = 12

4 0

4 years ago

Find the values of x and y that make these triangles congruent by the HL Theorem.

RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0

3 years ago

There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select

Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0

3 years ago

What is the perimeter of ΔABC?

Serggg [28]

Answer:

Choice D: Perimeter = 5 + $\sqrt{65}$ + $\sqrt{34}$ units

Step-by-step explanation:

point B(9, 2) , point C(4, 5), point A (1,1)

Perimeter = D( A, C) + D (A, B) + D (B, C)

where D (A, C) = distance between A and C

so...

D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5 from a 3-4-5 right triangle.

D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)

D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)

Perimeter = 5 + root(65) + root(34)

Perimeter = 5 + $\sqrt{65}$ + $\sqrt{34}$ units

6 0

3 years ago

Anyone please help me check these answers? I'm stressing out and in a panic mode because I may not finish 9th grade. Please help

anygoal [31]

Pic 1 is correct
Pic 2 is correct
Pic 3 is correct

4 0

3 years ago