Answer:
P(z>1.3) = 0.9032
Step-by-step explanation:
We are given:
Mean = 5000
Standard deviation = 1000
x = 6300
P(x>6300)=?
z-score =?
z-score = x- mean/standard deviation
z-score = 6300 - 5000/1000
z- score = 1300/1000
z-score = 1.3
So, P(x>6300) = P(z>1.3)
Looking at the z-probability distribution table and finding value:
P(z>1.3) = 0.9032
So, P(z>1.3) = 0.9032
Answer: 0.1 OR 1/10
Step-by-step explanation:
Think about it: There's 1/2 bag of oranges, and you wanna know what number of oranges used in the juice. Take 1/2, and divided it by 5. You get 0.1, then you should turn it into a fraction, giving you 1/10.
