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3 years ago

Boyd’s dartboard is octagonal. Each side measures 9 in. He drew a copy of the board that was smaller by a scale factor 0.25.

1 answer:

5 0

The question is about the side length of a copy of the dartboard. We know that the original dartboard has sides that measure 9 inches. We also have the scale factor 0.25. The ratio of the corresponding sides is called the scale factor. If we have the scale factor 0.25 it means that for 1 unit of the original figure there are 0.25 units of length of a copy. Therefore: x = 9 * 0.25; x = 2.25 in. Answer: The side length of the dartboard Boyd drew is 2.25 inches.

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The graph of a proportional relationship contains the point (20, 4).

soldier1979 [14.2K]

Answer:

$y=\frac{1}{5}x$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have

$point (20,4)$

Substitute the values and solve for k

$k=y/x$

$k=\frac{4}{20} =\frac{1}{5}$

therefore

the equation of the line is equal to

$y=\frac{1}{5}x$

6 0

3 years ago

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How much money would need to be deposited into an account earning 5.75% interest compounded annually in order for the accumulate

Leona [35]

I will assume you are using compound interest.

let the amount invested be x 

x(1.0575)^25 = 85000 
x = 85000/1.0575^25 = $21,009.20

6 0

3 years ago

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Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a

Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$p = 0.65, n = 153$ . So

$\mu = E(X) = 153*0.65 = 99.45$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9$

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{94 - 99.45}{5.9}$

$Z = -0.92$

$Z = -0.92$ has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

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3 years ago

7th grade math help me plzzzzzzz

Alex17521 [72]

Answer:

1. -60

2. 32

Step-by-step explanation:

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So we need to explain how we know 21/30 is greater than 2/3. Well lets expand 2/3 by multiplying the numerator and the denumerator by 10. That way we get 20 / 30. Since 21/30 has 1/30 more than 20/30 we can clearly see that 21/30 is greater than 20/30 or 2/3.

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3 years ago