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Goshia [24]
2 years ago
12

A mobile phone carrier charges an extra fee if a customer uses more than 500 minutes each month. Tom has already used 230 minute

s this month. Which in E quality can be used to determine how many more minutes Tom can use this month without going over the 500 minute limit?
Mathematics
1 answer:
mina [271]2 years ago
7 0
I think it’s 230+x is greater than or equal to 500.
I don’t have the greater than or equal sign in my phone lol
You might be interested in
Im stuck on this question helm me out I will mark you as brainliest​
agasfer [191]

Answer: <em><u>it is =4176000000000000</u></em>

Step-by-step explanation:

(2.9)(100000)(7.2)(10^2)

5(10^−8)

=

(290000)(7.2)(10^2)

5(10^−8)

=

2088000(10^2)

5(10^−8)

=

(2088000)(100)

5(10^−8)

=

208800000

5(10^−8)

=

208800000

5(1/100000000)=

208800000/1

20000000

=4176000000000000

hope i helped

-lvr

8 0
3 years ago
Question 3. Solve each equation given<br>below.<br>5 x - 4=31​
harkovskaia [24]

Answer:

x = 7

Step-by-step explanation:

5x-4 = 31

5x = 31+4

5x = 35

x = 7

3 0
2 years ago
I need help please. Thank you.
iVinArrow [24]

Answer:

i think it is 0 over 3

Step-by-step explanation:

4 0
3 years ago
The angle measurements in the diagram are represented by the following expressions.
AfilCa [17]

Given:

\angle A=10 x+24^{\circ}

\angle B=6 x+72^{\circ}

To find:

The value of x and measure of ∠A.

Solution:

Let C be angle the vertically opposite to ∠A.

The reference image for answer is attached below.

By vertical angle theorem:

m∠A = m∠C

m∠C = 10x + 24°

By the corresponding angle theorem:

m∠C = m∠B

10x + 24^\circ = 6x+72^\circ

Subtract 24° on both sides.

10x = 6x+48^\circ

Subtract 6x from both sides.

4x=48^\circ

Divide by 4 on both sides.

x = 12^\circ

The value of x is 12°.

\angle A=10 x+24^{\circ}

     =10 (12^{\circ})+24^{\circ}

     =144^\circ

The measure of ∠A is 144°.

5 0
2 years ago
I don't know how to do this please help explain how to do it aswell as give the answer so i understand
Zinaida [17]

<u>We are given:</u>

The function: y = -16t² + 64

where y is the height from ground, t seconds after falling

<u>Part A:</u>

when the droplet would hit the ground, it's height from the ground will be 0

replacing that in the given function:

0 = -16t² + 64

16t² = 64                          [adding 16t² on both sides]

t² = 4                                [dividing both sides by 16]

t = 2 seconds                  [taking square root of both sides]

<u>Part B:</u>

for second droplet,

height from ground = 16 feet

time taken = t seconds

acceleration due to gravity = 10 m/s²

initial velocity = 0 m/s

h = ut + (1/2)at²                 [second equation of motion]

16 = (0)(t) + (1/2)(10)(t²)

16 = 5t²

t² = 16/5

t = 1.8 seconds (approx)

Therefore, the second droplet takes the least amount time to hit the ground

4 0
3 years ago
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