Answer:
5 11/45
Step-by-step explanation:
1st, write them as improper fractions (so it is easier)
(121/9)-(41/5)
Next, make the fractions have the same denominator b finding their LCD
121/9-->605/45
41/5-->369/45
now subtract
605/45-369/45=236/45 or 5 11/45
Hope this helps ur sis
Answer:
f= 5k-2/-k+2
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
Answer:
i can np
Step-by-step explanation:
Solution:
LHS = (cosA+cosB)²+(sinA+sinB)²
= (cos²A+2cosAcosB+cos²B)+
(sin²A+2sinAsinB+sin²B)
/* By algebraic identity:
(x+y)² = x²+2xy+y² */
Rearranging the terms, we get
= (cos²A+sin²A)+(cos²B+sin²B)+2(cosAcosB+sinAsinB)
= 1+1+2cos(A-B)
________________________
we know that,
i) cos²x + sin²x = 1
ii) cosxcosy+sinxsiny = sin(x-y)
________________________
= 2+2cos(A-B)
= 2[1+cos(A-B)]
=
=
=$RHS$
Therefore,
(cosA+cosB)²+(sinA+sinB)²
=
••••
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