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Gnom [1K]
3 years ago
10

A caterpillar crawling in a straight line across a coordinate plane starts at point (-3, -4) and ends at point (25, 38). Countin

g the start point and end point, how many points with integer coordinates does the caterpillar touch?
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

15 points

Step-by-step explanation:

The start and end point of the caterpillar path are;

Start point = (-3, -4)

End point = (25, 38)

The slope of the caterpillar's path, 'm', given the 'x', and y-coordinates of two points is given by the following formula;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore, m = (38 - (-4))/(25 - (-3)) = 1.5

The equation of the caterpillar's path in point and slope form is given as follows;

y - (-4) = 1.5 × (x - (-3))

y + 4 = 1.5 × (x + 3)

y + 4 = 1.5·x + 4.5

y = 1.5·x + 4.5 - 4 = 1.5·x + 0.5

y = 1.5·x + 0.5

Given that the 0.5 is added to the product of 'x' and 1.5, the points that have both integer points for 'x', and 'y' are the points that have odd number values of 'x', as follows;

(-3, -4), (-1, -1), (1, 2), (3, 5), (5, 8), (7, 11), (9, 14), (11, 17), (13, 20), (15, 23), (17, 26), (19, 29), (21, 32), (23, 35), (25, 38)

Therefore, we have 15 points counting the start and end points with integer coordinates

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300-297+294-291+288-285+...+6-3
vladimir2022 [97]
300 - 297 = 3

294 - 291 = 3

288 - 285 = 3

So, that is a sequence of sums of number 3: 3 + 3 + 3 + .... + 3

How may times will the number 3 be added?

Note that 300 is reduced in 6 units each time => 300 / 6 = 50 => 3 will be added 50 times.

=> 50 * 3 = 150

Answer: 150
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If the equation y² - (K-<br>2y + 2k +1 = 0<br>with equal roots find the value of k​
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Answer:

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(k-2)^2 - 4(1)(2k+1) = 0

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Explain how to estimate the quotient using compatible numbers. 27 and two-thirds divided by 3 and StartFraction 9 over 10
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Answer:

Step-by-step explanation:

Given:

27 + 2/3 ÷ 3 + 9/10

In division, compatible numbers are numbers that can be divided mentally.

27 + 2/3 ÷ 3 + 9/10

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