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Sidana [21]
3 years ago
7

What is the value of x in this equation? −4x+8=42

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
X=-8.5

-4x+8=42
-8. -8
-4x=34
~. ~
4. 4

X=-8.5
Nady [450]3 years ago
4 0

Answer:

x = -8.5

Step-by-step explanation:

-4x+8=42

first subtract both sides by 8

-4x = 34

divide both sides by negative 4

x = -8.5

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The answer would be 3,712.5 feet im prettyyyy sure
7 0
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Which of the following are NOT the lengths of the sides of a triangle?
Evgesh-ka [11]
2,3,6 because 2 and 3 cant equal 6

7 0
3 years ago
A cyclist rides in a circle with speed 5 m/s. What is his centripetal
Anna71 [15]

Option A

The centripetal acceleration is 1.32 ms^{-2}

<em><u>Solution:</u></em>

From given question,

A cyclist rides in a circle with speed 5 m/s

The circle has a radius of 19 m

To find: Centripetal acceleration

<em><u>The formula for Centripetal acceleration is given as:</u></em>

a_c = \frac{v^2}{r}

Where,

a_c = centripetal acceleration

r is the radius and v is the velocity

From given statement,

radius = r = 19 m

velocity = v = 5 m/s

<em><u>Substituting the values in above formula, we get</u></em>

a_c = \frac{5^2}{19}\\\\a_c = \frac{25}{19}\\\\a_c = 1.315 \approx 1.32

Thus centripetal acceleration is 1.32 ms^{-2}

6 0
3 years ago
Consider the figure to complete the statement.
Keith_Richards [23]

Answer: 55 degrees / Acute angle.

Step-by-step explanation:

The angle is less than a right angle, bent forward so it's less than 90 degrees, meaning it's an acute angle.

8 0
4 years ago
Which value cannot represent the probability of an event occurring? StartFraction 1 over 100 EndFraction 0. 29 85% Three-half.
Serjik [45]

Every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.

Given to us,

a.)  \dfrac{1}{100}

b.)  0.29

c.)  85%

d.)  \dfrac{3}{2}

The probability help us to know about the probability of specific events occurring.

For a sure event, the probability is always 1,

while for an event that will never happen the probability is always 0.

Thus, probability(p),  \bold{1 \geq p\geq 0}.

Now looking at the options,

a.)  \dfrac{1}{100} = 0.01

b.)  0.29

c.)  85% = 0.85

d.)  \dfrac{3}{2} = 1.5

Now comparing each option with \bold{1 \geq p\geq 0}.

Therefore, the only option which is not feasible is option d that is 1.5.

Hence, every value{0.01, 0.29, 85%} can represent the probability of an event occurring except option d that is 1.5.

To know more visit:

brainly.com/question/795909

3 0
2 years ago
Read 2 more answers
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