Given 25x^2 - 10x = 0, which values of x will satisfy the equation? (Hint: Factor the polynomial into two terms, and find the va
lues of x that will make each term 0.). . A. x = 0 and x = 5/2. . B. x = 0 and x = 2/5. . C. x = 0 and x = 2. . D. x = 0 and x = 5
2 answers:
25 x² - 10 x = 0
5 x ( 5 x - 2 ) = 0
x = 0 and
5 x - 2 = 0
5 x = 2
x = 2: 5
x = 2/5
Answer: B ) x = 0 and x = 2/5
Answer:
B. x = 0 and x = 2/5
Step-by-step explanation:
To get the value satisfying the equation, we will need to simplify the given equation 25x²-10x = 0 to have:
First we will factor out '5x' which a common factor to have;
5x(5x - 2) = 0
5x = 0 and 5x-2 = 0
From 5x = 0, x =0
From equation 5x-2=0, 5x= 0+2
5x = 2
Dividing both sides by 5 which is the coefficient of x we have;
5x/5 = 2/5
x = 2/5
The solutions will give;
x = 0 and x = 2/5
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==>10-4x²-7x-3x+6x²=?
==>?=2x²-10x+10