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igomit [66]
3 years ago
5

PLEASE HELP FREE 15 POINTS

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

19.5 because if we do hundred then it well equal to 19.5

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Use the model to solve for x.
Vitek1552 [10]
Answer:No solution
Explanation: There is no solution because x was eliminated in the last step of solving for x. Since we were left with x not being available to equal three, it shows it’s a no solution problem. Hope this helped!

4 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Write using only positive exponents. 16x^4z^4/36x-2yz^0
kolbaska11 [484]

Answer:

Step-by-step explanation:

16x^4y^-3z^4 / 36x^-2yz^0

16x^4y^-3z^4 = 16x^4z^4/y^3

36x^-2yz^0 = 36x^-2y(1) =36x^-2y = 36y/x^2

16x^4y^-3z^4 / 36x^-2yz^0

= (16x^4z^4/y^3) / (36y/x^2)

= 16x^4z^4/y^3 * x^2/36y  

= (4/9)x^6z^4/y^4

or another way

fist multiply it out

f(x) = 4x^(3/5) - x^(8/5)

now differentiate knowing d/dx(x^n) = n x^(n-1)

to get

4*(3/5) x^(-2/5) - 8/5 x^(3/5)

simplify to get

12/5/x^(2/5) -   8/5 x^(3/5)

If this is what your looking for please give me brainiest, i have done this problem in the past so i know how to solve it :)

5 0
3 years ago
For science class, a student recorded the high and low temperatures, in Fahrenheit, over a ten day period in September. The data
statuscvo [17]

Answer:

hdghjdguwa

Step-by-step explanation:

dznsdgb

5 0
3 years ago
Write a factor pair of 13
Serga [27]
A factor pair of 13 would be:

1 * 13
or
13 * 1

Hope this helps!
4 0
3 years ago
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