Plsss helppp, tysmm!!

Please help A.S.A.P it's due tomorrow morning? what is y = 2x + 5 and f(x) = 2x + 5

amid [387]

Answer:

they are equal

Step-by-step explanation:

f(x) means the same thing as y.

3 0

3 years ago

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8 cm 5 cm 10 cm 12 cm

lana66690 [7]

Answer:

35 cm

Step-by-step explanation:

6 0

3 years ago

A juice recipe calls for 5 cups of grape juice for every 2 cups of peach juice are needed for a batch that uses 8 cups of peach

Ksivusya [100]

Answer: 20 cups of grape juice are needed for 8 cups of peach juice.

Step-by-step explanation:

5 times 4 is 20.

We must do this step because you need 2 cups for 1 batch, and times 4 that is 8. So then we multiplied 5 times 4.

So, 20 cups of grape juice are needed for 8 cups of peach juice.

Hope this answer helps you out!

3 0

3 years ago

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For a field trip 20 students rode in cars and the rest filled 5 busses. How many students were in each bus if 210 students were

xeze [42]

First do 210 - 20 = 190
Then do 190/5 = 38
38 people per bus is the answer!!!!

3 0

3 years ago

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A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes

Elena L [17]

Answer:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

$\hat p=\frac{282}{830}=0.340$ estimated proportion of people that regularly watch the TV station’s news program

$p_o=0.38$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:

Null hypothesis: $p\geq 0.38$

Alternative hypothesis: $p < 0.38$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

3 0

3 years ago