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3 years ago

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A chocolate company selects 50 random packages and checks their weight. It finds that 2 packages have an incorrect weight. How m

any packages out of 2000 should the company predict have an incorrect weight?

1 answer:

Anna35 [415]3 years ago

5 0

Answer:

80 out of 2000 packages are expected to have an incorrect weight.

Step-by-step explanation:

2000×0.04 = 80

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A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago

Find the area of the shaped region

Ganezh [65]

Answer: B

Step-by-step explanation:

A = 0/360 ×π×r^2

=135/360×π×11×11

=142.55 yd^2

5 0

2 years ago

A 30-foot ladder is leaning against an office building. if the base of the ladder is

Lina20 [59]

Angle of elevation would be 66 degrees

4 0

1 year ago

What is the sum of the 12th square number and the 9th square number

Inessa [10]

Answer: 225

Step-by-step explanation:

<u>What is a square number</u>?

A square number is a product of a number times itself

So, the 12th square number would be 12 * 12, or 12²

The 9th square number would be 9 * 9, or 9²

The equation would be 12² + 9²

So:

12² + 9²

= 144 + 81

= 225

So, the answer is 225

6 0

1 year ago

Find the perimeter of OQR if OQ=6.5.<br> A.<br> 6.1<br> B.<br> 12.2<br> C.<br> 13<br> D.<br> 19.1

Svetach [21]

ANSWER

The correct answer is 19.1

EXPLANATION

The perimeter of triangle OQR is the sum of the distance around the triangle.

Thus,

$Perimeter=|OQ|+|OR|+|RQ|$

We can observe that two of the angles are equal.

The angles that are equal measures 62° each.

Therefore triangle OQR is an isosceles triangle. This means that

$|OQ|=6.5=|OR|$

Hence,

$Perimeter=6.5+6.5+6.1$

$Perimeter=19.1$ units.

3 0

2 years ago

Read 2 more answers