5p+2r=q
Move variable to the right
5p=q -2r
Divide both sides of the
equation by 5
q - 2
p =— — r
5 - 5
The final solution for
p is
q - 2
p =— — r, rER, qER
5 - 5
I cannot make the E like it should be made in mathematics on this keyboard. An elongated E.
You need the Law of Cosines here. Let's call our given angle A, so the side across from it, the one we are looking to solve for, would be a. The Law is as follows then:
![a^2=27^2+31^2-[2(27)(31)cos(75)]](https://tex.z-dn.net/?f=a%5E2%3D27%5E2%2B31%5E2-%5B2%2827%29%2831%29cos%2875%29%5D)
. We will simplify everything here at once to get
.
so a = 35.5
The 10 tons should have 37.9% cement.
Let the 25% mixture be x tons
Then the 68% mixture will be (10 -x) tons.
Using formula for mixtures:
Let p for percentage and w for weight in tons.
p₁w₁ + p₂w₂ = pw
25*x + 68*(10-x) = 37.9*10
25x + 680 - 68x = 379
680 - 43x = 379
680 - 379 = 43x
301 = 43x
43x = 301
x = 301/43
x = 7
Recall that x, was for the 25% mixture, 7 tons.
a) For the 68% mixture, = 10 - x = 10 -7 = 3 tons.
b) For the 25% mixture = x = 7 tons.
Answer:
It's 4-12x
Step-by-step explanation:
Answer:
x=-2/15
Step-by-step explanation:
