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Question</h2>
6.A small ball is dropped from a tall building.which equation could present the ball's height, <em>h</em>, in feet, relative to the ground, as a function of time, <em>t</em><em>,</em>in seconds
✒ Answer
Answer:
1/4.(-96)=2x-3
-1/4.96=2x-3
-24=2x-3
-2x-24=-3
-2x=-3+24
-2x=21
x=-21/2
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
(9x + 10)° = 136°
9x + 10 = 136
9x = 126
x = 14
Answer:
0.24
Step-by-step explanation:
it was 0.24161073 not simplified but since the 1 after the 4 is not greater than five it stays the same and it beccome 0.24
Answer:
Step-by-step explanation:
Question (1).
OQ and RT are the parallel lines and UN is a transversal intersecting these lines at two different points P and S.
A). ∠OPS ≅ ∠RSU [corresponding angles]
B). m∠OPS + m∠RSP = 180° [Consecutive interior angles]
C). m∠OPS + m∠OPN = 180° [Linear pair of angles]
D). Since, ∠OPS ≅ ∠TSP [Alternate interior angles]
And m∠TSP + m∠TSU = 180° [Linear pair of angles]
Therefore, Option (A) is the correct option.
Question (2).
A). m∠RSP + m∠RSU = 180° [Linear pair of angles]
B). m∠RSP + m∠PST = 180° [Linear pair of angles]
C). ∠RSP ≅ ∠TSU [Vertically opposite angles]
D). m∠RSP + m∠OPS = 180° [Consecutive interior angles]
Therefore, Option (C) will be the answer.
