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Mandarinka [93]

2 years ago

15

Subtracting 5 from each score in a distribution with a mean equal to 40 and a standard deviation equal to 3 will result in a sta

ndard deviation equal to:

1 answer:

LenaWriter [7]2 years ago

6 0

Adding or subtracting a constant from each value of a distribution changes the mean, but not the standard deviation.

The standard deviation will equal 3.

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Direct Variation.<br>¯\_(ツ)_/¯

Alekssandra [29.7K]

Answer:

y = 1/6

Step-by-step explanation:

direct variation

y =kx

substitute in what we know to find k

1/2 = k*3

solve for k

divide by 3

1/2 /3 = k

1/6 = k

substitute k into the direct variation equation

y = 1/6 x

let x = 1

y = 1/6 *1

y = 1/6

5 0

3 years ago

-6z = 72<br> What is the solution

exis [7]

-6z = 72

Divide both sides by -6

-6z = 72
/-6 /-6

z = -12

6 0

3 years ago

Why does the fact family for 81 and 9 have only two number sentences

qwelly [4]

Because there are only two things you can do with these two " family" members. 81 divided by 9 is 9. 9 times 9 is 81. Strictly speaking, there should be three in the family: 9,9 and 81 9 is the square root of 81. 81 is the 9 squared.

8 0

3 years ago

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

Which number is rational, an integer, and a real number?

allochka39001 [22]

B is the correct if this multiple choice

6 0

3 years ago