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True [87]
2 years ago
9

Please help me I need to do this like now!!!!

Mathematics
2 answers:
mihalych1998 [28]2 years ago
3 0
Im PRETTY sure its 0 bc the words “Super awesome” dont have a “K” in them
lozanna [386]2 years ago
3 0

Answer:

0

Step-by-step explanation:

There's no letter "k" in the phrase "super awesome".

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What is the best approximation for the area of this circle?
Maslowich
To find the area of the circle you must use the formula

The radius length is 4 so you substitute it for 3.14

area=3.14 x 4^2
area=50.24

So the correct answer would be C.
4 0
3 years ago
Jeremy cleans his house in 2 1/2 hours. Hunter cleans his house in 3 1/4 hours. How much longer does it take Jeremy to clean a h
lubasha [3.4K]
2 1/2 becomes 2 2/4. 3 1/4-2 2/4 = 3/4 of an hour
6 0
3 years ago
Sandra wants to rent a car to take a trip and has a budget of $90. There is a fixed rental fee of $30 and a daily fee of $10. Wr
nikdorinn [45]

Option B is the correct answer

Step-by-step explanation:

Step 1 :

Given,

Maximum budget Sandra has for the trip is $90

Fixed rental fee = $30

Daily fee = $10

Step 2 :

Let x be the number of the days for which Sandra can go for the trip

If the daily fee is $10, the cost for x number of days would be 10*x

the fixed fee is $30

So the equation is represent the cost of the trip is 30 + 10 x

given that the maximum budget is $90, the above cost should always be less $90

So the required inequality is 30 + 10x ≤ 90

Option B is the correct answer

4 0
3 years ago
What is the answer to #4
vladimir2022 [97]

Answer:

A

Step-by-step explanation:

I am almost completely positive that question 4 is A

3 0
2 years ago
Read 2 more answers
NEED HELP WITH THIS PROBLEM!!!!!!
zzz [600]

Answer:

  \displaystyle\frac{\sqrt[4]{3x^2}}{2y}

Step-by-step explanation:

It can work well to identify 4th powers under the radical, then remove them.

  \displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}

_____

The applicable rules of exponents are ...

  1/a^b = a^-b

  (a^b)(a^c) = a^(b+c)

The x-factors simplify as ...

  x^6/x^4 = x^(6-4) = x^2

The y-factors simplify as ...

  y/y^5 = 1/y^(5-1) = 1/y^4

The constant factors simplify in the usual way:

  24/128 = (8·3)/(8·16) = 3/16

3 0
3 years ago
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