Answer:
16
Step-by-step explanation:
Answer:
288 is your answer. Your welcome
Solution :
The null and alternative hypothesis is given by


Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05
Answer: 2 is a given which is (SV | | TU)
I need help with the others.
Step-by-step explanation:
<u>Answer:</u>
The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is 
<u>Solution:</u>
Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.
We have to find the equation of the above polynomial.
We know that, general equation of 3rd degree polynomial is

where a, b, c are roots of the polynomial.
Here in our problem, a = 1, b = 2, c = -1.
Substitute the above values in f(x)


So, the equation is 
Let us put x = 0 in f(x) to check whether our answer is correct or not.

Hence, the equation of the polynomial is 