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True [87]
2 years ago
9

Please help me I need to do this like now!!!!

Mathematics
2 answers:
mihalych1998 [28]2 years ago
3 0
Im PRETTY sure its 0 bc the words “Super awesome” dont have a “K” in them
lozanna [386]2 years ago
3 0

Answer:

0

Step-by-step explanation:

There's no letter "k" in the phrase "super awesome".

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A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
A builder is buying property where she can build new houses the line plot shows the size of the lights for each house which is t
arlik [135]

Answer:

TBH IDRK

Step-by-step explanation:

You do what ever ask ur teacher not me im  on here looking for answers myself lmbo

6 0
3 years ago
Read 2 more answers
What is the equation of the line? It’s iReady please help meeeehh
anyanavicka [17]
The answer I think is Y= 2x-4
Start on the x axis then read the y axis , because the line goes through on the left it would be -
8 0
3 years ago
Prisha rolls a fair number cube multiple times and records the result of each roll. Her results are shown in the table.
Leona [35]

Answer:

The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3

Step-by-step explanation:

* Lets explain the difference between the theoretical probability and

 experimental probability

- Theoretical probability is what we expect to happen

- Experimental probability is what actually happens when we try it out

- Both of them calculated by the same way, the number of possible ways

 an outcome can occur divided by the total

* Lets solve the problem

- The table has two column;

# Number Cube             # Observed Frequency

           1                                           18

           2                                          16

           3                                          24

           4                                          26

           5                                          16

           6                                          20

        Total                                      120

∵ The experimental probability of rolling a 3 = 24/120 = 1/5 = 0.2

∴ The experimental probability of rolling a 3 = 0.2 = 20%

∵ The theoretical probability of rolling a 3 = 1/6

∴ The theoretical probability of rolling a 3 = 0.1666 ≅ 17%

∵ 20% is greater than 17%

∴ The experimental probability of rolling a 3 is greater than the

  theoretical probability of rolling a 3

7 0
3 years ago
Read 3 more answers
In the historical account of Rome, another name for the Romans is the
zlopas [31]

Answer:

what ?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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