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True [87]
2 years ago
9

Please help me I need to do this like now!!!!

Mathematics
2 answers:
mihalych1998 [28]2 years ago
3 0
Im PRETTY sure its 0 bc the words “Super awesome” dont have a “K” in them
lozanna [386]2 years ago
3 0

Answer:

0

Step-by-step explanation:

There's no letter "k" in the phrase "super awesome".

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5 ) ( 8 x 10 - 82 ) - 8​
juin [17]

Answer:

16

Step-by-step explanation:

7 0
3 years ago
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What is the least common multiple of 32 24 and 18
noname [10]

Answer:

288 is your answer. Your welcome

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3 years ago
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Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data
EastWind [94]

Solution :

The null and alternative hypothesis is given by

$H_0: \mu = 11$

$H_a: \mu \ne 11$

Assume that the level of significance, α = 0.05

The t-test statistics is, t = 1.484

Degree of freedom :

df = n - 1

   = 14 - 1

   = 13

The P-value is given by

P-value = 2P (T>|t|)

            = 2P(T>|1.484|)

            = 2P(T>1.484)

            = 2(=T.DIST.RT(1.484,13))

            = 0.05

5 0
3 years ago
Given: SV || TU and SVX = UTX
Vladimir [108]

Answer: 2 is a given which is (SV | | TU)

I need help with the others.

Step-by-step explanation:

7 0
3 years ago
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
3 years ago
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