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Feliz [49]
3 years ago
5

A mountain bike originally priced at $960.00 is up for sale at a discount of 14%. What is the price of the mountain bike after t

he discount?
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

$825.60

Step-by-step explanation:

Since the price of it is $960.00, it means that it's 100%.

100% = 960

1% = 960 ÷ 100 = 9.6

14% = 9.6 x 14 = 134.40

Since they asked for after the discount, deduct the price of the discount with the original price.

Mountain bike after 14% discount =

960 - 134.40 = 825.60

Step2247 [10]3 years ago
7 0
960.00x0.14= 134.4

960.00 - 134.4 = 825.6 < answer
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Which expression is equivalent to √900f^6/100g^4
krek1111 [17]

Answer:

A

Step-by-step explanation:

c and d cannot be since the answer to sqrt((900f^6)/(100g^4)) is 3f³/g²

and not 30f something.

the best answer I see is correct is a.

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3 years ago
Dawn bought 12 grams of chocolate. she ate half of the chocolate. How many grams of chocolate did she eat?
andre [41]
Half of twelve is six.

She ate 6 grams.
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3 years ago
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Simplify (8m² + 3m - 5) + (m² - 7m - 1)
Rus_ich [418]

Answer:

9m^2 - 4m - 6

Step-by-step explanation: hope this helps!

8 0
2 years ago
Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean
Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = <u>4.8</u>

4. x ≈ <u>14.48</u>

5. x ≈ <u>11.37</u>

6. G.M. = <u>12·√3</u>

7. G.M. = <u>6·√5</u>

<u />

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK  = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

  • <u>ΔLJK is similar to ΔKJM</u> by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

  • <u>ΔLJK is similar to ΔLKM</u> by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

  • <u>ΔKJM ~ ΔLKM</u>

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

  • <u>ΔYWZ is similar to ΔZWX</u>, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

  • <u>ΔYWZ is similar to ΔYZW</u> by AA similarity postulate

Therefore;

  • <u>ΔZWX ~ ΔYZW</u>

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}

8 × 6 = 10 × x

48 = 10·x

  • x = \dfrac{48}{10} = \underline{4.8}

3. From the similar triangles, we have;

\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}

20 × 21 = x × 29

420 = 29·x

  • x = \dfrac{420}{29 } \approx \underline{14.48}

4. From the similar triangles, we have;

\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}

20 × 48 = 52 × x

  • x = \dfrac{20 \times 48}{52}  = \dfrac{240}{13}  \approx \underline{18.46}

5. From the similar triangles, we have;

\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}

13.2 × 22.4 = 26 × x

  • x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}

6. The geometric mean, G.M. is given by the formula;

G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3  ... x_n}}

The geometric mean of 16 and 27 is therefore;

  • G.M. = \sqrt[2]{16 \times 27}  = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}

  • The geometric mean of 16 and 27 is <u>12·√3</u>

<u />

7. The geometric mean of 5 and 36 is found as follows;

G.M. = \sqrt[2]{5 \times 36}  = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}

  • The geometric mean of 5 and 36 is <u>6·√5</u>

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0
2 years ago
Find anequation of the line containing (3,-4) and having slope -2. If this line
Stells [14]

Answer:

A linear equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we want to have a slope equal to -2, then our line will be something like:

y = -2*x + b

Now, we also want this line to pass through the point (3, -4)

This means that when x = 3, we must have y = -4

Then:

-4 = -2*(3) + b

-4 = -6 + b

-4 + 6 = b

2 = b

Then our line is:

y = -2*x + 2

Now, the second part says that:

If this line  contains the points (2,8) and (5.b), find a and b.​

This is incorrectly written because this line clearly does not contain the point (2, 8), so i guess the actual problem is something like:

If this line  contains the points (a,8) and (5.b), find a and b.​

If the line contains the point (a, 8), this means that when y = 8, we must have x = a.

Then:

8 = -2*a + 2

8 - 2 = -2*a

6 = -2*a

6/-2 = -3 = a

a = -3

Similar reasoing for the other point, if the line contains the point (5, b), this means that when x = 5, we have y = b.

Then:

b = -2*5 + 2 = -10 + 2

b = -8

7 0
2 years ago
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