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3 years ago

A family needs to build fencing around their rectangular

Mathematics

2 answers:

lilavasa [31]3 years ago

8 0

Answer:

160

Step-by-step explanation:

If you are given a rectangular home and a square swimming pool, with dimensions of Pool = 2x & home = (2 +5x) & (3+10x) The total amount of fencing they need can be written as x + 10. If x = 5; The family needs 5 yards of fencing for their home. The family needs 10 yards of fencing for their pool.

may I have brainliest?

cluponka [151]3 years ago

5 0

38

160

40

Hope it helps

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On a 15-mile race, runners start with a 9-mile road race followed by 12 laps around a track that is x miles long. What is the le

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Answer:

2 miles

Step-by-step explanation:

15 miles - 9 miles = 6 miles

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3 years ago

Lacy has a $1000 bond with a 6.2% coupon that she purchased for $1025. What is the yield of this bond? Round your answer to 2 de

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3 years ago

Read 2 more answers

Hi im new and i need help picture below, please help, thank you :)

lbvjy [14]

Answer:

x = 80 degrees

Step-by-step explanation:

y degrees = 180 - 55 - 45 (Angles in a triangle add up to 180 degrees)

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x = y (Vertically opposite angles are equal)

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x = 80 degrees

8 0

3 years ago

What is the equation of this line?

Illusion [34]

Y=-4
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5 0

4 years ago

An economist is studying the job market in Denver area neighborhoods. Let x represent the total number of jobs in a given neighb

lbvjy [14]

Answer:

a) $\sum X = 13+34+52+28+50+25 =202$

$\sum Y = 1+4+5+5+9+3= 27$

$\sum X^2 = 13^2+34^2+52^2+28^2+50^2+25^2 = 1074$

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

$r=\frac{6(1074)-(202)(27)}{\sqrt{[6(7938) -(202)^2][6(157) -(202)^2]}}=0.821$

b) $m=\frac{165}{1137.33}=0.145$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{202}{6}=33.67$

$\bar y= \frac{\sum y_i}{n}=\frac{27}{6}=4.5$

And we can find the intercept using this:

$b=\bar y -m \bar x=4.5-(0.145*33.67)=-0.384$

So the line would be given by:

$y=0.145 x -0.384$

c) The coefficient of variation is given by:

$r^2 = 0.821^2 = 0.674$

And we can conclude that 67.4% of the variation in y can be explainedby the corresponding variation in x and the least-squares line

d) For this case we just need to replade x = 34 into our model and we got:

$y=0.145*34 -0.384= 3.097$

Step-by-step explanation:

For this case we have the following data:

x 13 34 52 28 50 25

y 1 4 5 5 9 3

Part a

$\sum X = 13+34+52+28+50+25 =202$

$\sum Y = 1+4+5+5+9+3= 27$

$\sum X^2 = 13^2+34^2+52^2+28^2+50^2+25^2 = 1074$

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

$r=\frac{6(1074)-(202)(27)}{\sqrt{[6(7938) -(202)^2][6(157) -(202)^2]}}=0.821$

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=7938-\frac{202^2}{6}=1137.33$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=1074-\frac{202*27}{6}=165$

And the slope would be:

$m=\frac{165}{1137.33}=0.145$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{202}{6}=33.67$

$\bar y= \frac{\sum y_i}{n}=\frac{27}{6}=4.5$

And we can find the intercept using this:

$b=\bar y -m \bar x=4.5-(0.145*33.67)=-0.384$

So the line would be given by:

$y=0.145 x -0.384$

Part c

The coefficient of variation is given by:

$r^2 = 0.821^2 = 0.674$

And we can conclude that 67.4% of the variation in y can be explainedby the corresponding variation in x and the least-squares line

Part d

For this case we just need to replade x = 34 into our model and we got:

$y=0.145*34 -0.384= 3.097$

3 0

4 years ago