Question

Identify the perimeter and area of a square with diagonal length 24in. Give your answer in simplest radical form!!!

Answer 1

Answer:

Perimeter: $48\sqrt{2} \: \mathrm{inches}$

Area: $288\mathrm \: \mathrm{square \: inches}$

Step-by-step explanation:

If the diagonal of the square is 24 inches, the side length of the square is $12\sqrt{2}$ inches ($2x^2=24^2$). The perimeter of this square is then $4 \cdot 12\sqrt{2}=\fbox{ 48\sqrt{2}\: \mathrm{in} }$ and the area $(12\sqrt{2})^2=\fbox{ 288\: \mathrm{in^2} }$.