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3 years ago

How many inches is that

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

Answer:

I wouldnt know.

Step-by-step explanation:

i think you forgot to attach the image, I’ll come back when you do. Just make sure to do that next time

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How do you solve, 5 ^3x-4/25=625

gtnhenbr [62]

Step-by-step explanation:

(5^3x*25-4)/25=625

125^3x-4=625*25

5^x-4=15625

5^x=15625-4

5^x=15621 I can't solved by me if there is only 15625 then the answer will be 6 because 5^6=15625 but there is -4 too

3 0

2 years ago

A medium artichoke contains about 14% of the recommended amount of a certain mineral an average adult should have each day. Abo

belka [17]

Answer:

0.0238 g

Step-by-step explanation:

Given that:

the certain mineral = potassium and a medium artichoke contain about 0.17 g of it.

Suppose a medium artichoke contains about 14% of the recommended amount of a certain mineral.

On Average, the amount an adult should have each day = 0.17 g × (14/100)

= 0.0238 g

5 0

3 years ago

Simplify the expression. 9r 3r2 – 5r 7

Ksenya-84 [330]

Your final answer is going to be 4r + 3r ^2 +7

7 0

3 years ago

Read 2 more answers

Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

6 0

2 years ago

(<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align="absmiddle" class="l

Alisiya [41]

(x^2-3x+2)-1(3x^2-5x-1)=
x^2-3x+2-3x^2+5x+1=
x^2-3x^2-3x+5x+2+1=
-2x^2+2x+3

4 0

3 years ago

Read 2 more answers