Answer:
(t^2 -4) (t^2 +4)
(t-2)(t+2)(t^2+4)
Step-by-step explanation:
t^4 - 16
We can write this as the difference of squares
We know the dfference of squares is
(a^2 - b^2) = (a-b) (a+b)
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)
We can write t^2 -4 as the difference of squares
t^2 -4 = t^2 -2^2 = (t-2)(t+2)
Replacing this in
( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) = (t-2)(t+2)(t^2+4)
Answer:
we determine that none of the ordered pair is a solution of
as none of the ordered pairs satisfy the equation.
Step-by-step explanation:
Considering the equation

- Putting (-5,2) in the equation


∵ L.H.S ≠ R.H.S
FALSE
- Putting (0,-5) in the equation


∵ L.H.S ≠ R.H.S
FALSE
- Putting (5,1) in the equation


∵ L.H.S ≠ R.H.S
FALSE
- Putting (7,5) in the equation


∵ L.H.S ≠ R.H.S
FALSE
From the above calculations, we determine that none of the ordered pair is a solution of
as none of the ordered pairs satisfy the equation.
Answer:
-1/2 ≤ x ≤ 3
Step-by-step explanation:
hope that helps