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dedylja [7]
2 years ago
11

What is an equation of the line that passes through the points (-2, 1) and (-8, 4)?

Mathematics
1 answer:
Grace [21]2 years ago
4 0

Answer:

<h2>3x + 6y = 0</h2>

Step-by-step explanation:

Equation of a line = y = mx + c

where m = slope

m = (1 - 4) / (-2 - (-8))

<h3>m = -3 / 6</h3>

y - 1 = -3/6 (x + 2)

6y - 6 = -3x - 6

3x + 6y = 0

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PLEASE HELP
lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


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3 years ago
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love history [14]
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3 years ago
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Delicious77 [7]
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3 years ago
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Answer:

i need the table

Step-by-step explanation:

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QveST [7]
The answer is 4 apples
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