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kifflom [539]
3 years ago
12

What is the y-value of the solution of the system of equations given below?

Mathematics
1 answer:
Savatey [412]3 years ago
4 0
Point form: (-2, 0)
Equation form: x=2, y=0
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In the diagram below, BD is parallel to XY. What is the value of y?
Volgvan
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8 0
3 years ago
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If f(x) = 4x and g(x) = 2x – 1, what is g(f(–2))?<br><br> A-17<br> B-13<br> C-8<br> D-5
kondaur [170]
F(x) = 4x
so f(-2) = 4*-2 = -8  
and 
g((f(-2)) = g(-8) =  -16-1 = -17

Its A
3 0
3 years ago
Please help me solve 5 and 6 for my homework
defon

Answer:

(5) The perpendicular height of the triangle is 8.48 mm.

(6) The 1184.86 cm far up the wall the ladder reach.

Step-by-step explanation:

Part (5):

When a perpendicular is drawn in an isosceles triangle then the perpendicular divided the base into 2 equal parts.

The figures is shown below.

In ΔABC,

CB = 6 mm

So,

CD = BD = 3 mm

Now calculating the perpendicular height of the triangle.

Using Pythagoras theorem in ΔADC:

(AC)^2=(CD)^2+(AD)^2\\\\(9)^2=(3)^2+(AD)^2\\\\81=9+(AD)^2\\\\(AD)^2=81-9\\\\(AD)^2=72\\\\AD=8.48mm

Thus, the perpendicular height of the triangle is 8.48 mm.

Part (6):

The figure is shown below.

Converting meter to centimeter:

1 m = 100 cm

So,

12 m = 1200 cm

Using Pythagoras theorem in ΔXYZ:

(XZ)^2=(YZ)^2+(XY)^2\\\\(1200)^2=(190)^2+(XY)^2\\\\1440000=36100+(XY)^2\\\\(XY)^2=1440000-36100\\\\(XY)^2=1403900\\\\XY=1184.86cm

Thus, 1184.86 cm far up the wall the ladder reach.

4 0
3 years ago
Greatest common factor of 12, 60, and 68
Katyanochek1 [597]
To calculate the GCF, you need to list all the prime numbers that will go into each number listed

12: 2, 2, 3
60: 2, 2, 3 5
68: 2,2,17

Now you circle the numbers that are the same in each.

GCF: 2, 2

Multiply these numbers to find the GCF: 4
5 0
3 years ago
Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
romanna [79]

Answer:

11x+y = -28

Step-by-step explanation:

We have two points so we can find the slope

m = (y2-y2)/(x2-x1)

   = (-6-5)/ (-2--3)

   = -11(-2+3)

   = -11/1

The slope is -11

We can use point slope to make an equation

y-y1 = m (x-x1)

y-5 = -11(x--3)

y -5 = -11(x+3)

Distribute

y-5 = -11x-33

Add 5 to each side

y-5+5 = -11x-33+5

y = -11x-28

Add 11x to each side

11x+y = -11x+11x-28

11x+y = -28

This is the standard form of a line

5 0
4 years ago
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