Question

X+y+z=−4 2x+3y−2z=10 −x+2y−3z=−12 solve for x,y,z WILL MARK BRAINLIEST!!!

Answer 1

Answer:

x = 13

y = -10

z = -7

Step-by-step explanation:

x+y+z=−4

2x+3y−2z=10

−x+2y−3z=−12

Add the first and the third equations to eliminate x

x+y+z=−4

−x+2y−3z=−12

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  3y -2z = -16  Equation A

Add the second and twice the third equation to eliminate x

2x+3y−2z=10

−2x+4y−6z=−24

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     7y -8z = -14  Equation B

Take Equation A and multiply by -4

-4*(  3y -2z) = (-16)*-4

-12y + 8z = 64

Add this to Equation B

-12y + 8z = 64

 7y -8z = -14

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-5y = 50

Divide by -5

-5y/-5 = 50/-5

y = -10

Now using equation A

  3y -2z = -16  

3*-10 -2z = -16

-30 -2z = -16

Add 30 to each side

-2z = -16+30

-2z = 14

Divide by -2

-2z/-2 = 14/-2

z = -7

Now find x using the first equation

x+y+z = -4

x -7-10 = -4

x -17 = -4

Add 17 to each side

x-17+17 = -4+17

x = 13