You are supposed to add all of those numbers and then divide by how many ever numbers there are.
Mean (average) can be found by adding up all the numbers and then dividing that by how many numbers there are.
(5+10+12+4+6+11+13+5) / 8 = 66/8 = 8.25 <==
the mode (the number used most often) = 5....just so u know, there doesn't have to be a mode, and sometimes there is more then 1 mode. But for this one, the mode is 5. <==
median (the middle number)...for this, u put the numbers in order...
4,5,5,(6,10),11,12,13
now start moving from both ends going inward until u find the middle number...keep in mind, when u have an odd number of numbers, u will have 1 middle number.....but when there is an even number of numbers, like in this case, u will have 2 middle numbers...so u take ur 2 middle numbers, add them, then divide by 2 to get ur median.
median = (6 + 10) / 2 = 16/2 = 8 <==
Answer:
B
Step-by-step explanation:
Tell me if you need an explanation
Answer:
It shows how much variable is affected by one another.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Descartes' rule of signs tells you this function, with its signs {- - - + +}, having one sign change, will have one positive real root.
When odd-degree terms have their signs changed, the signs {- + - - +} have three changes, so there will be 1 or 3 negative real roots.
The constant term (10) tells us the y-intercept is positive. The sum of coefficients is -11 -5 -9 +12 +10 = -3, so f(1) < 0 and there is a root between 0 and 1.
When odd-degree coefficients change sign, the sum becomes -11 +5 -9 -12+10 = -17, so there is a root between -1 and 0.
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Synthetic division by (x+1) gives a quotient of -11x^3 +6x^2 -15x +27 -17/(x+1), which has alternating signs, indicating -1 is a lower bound on real roots.
Real roots are located in the intervals [-1, 0] and [0, 1].
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The remaining roots are complex. All roots are irrational.
The attached graph confirms that roots are in the intervals listed here. Newton's method iteration is used to refine these to calculator precision. Dividing them from f(x) gives a quadratic with irrational coefficients and complex roots.